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3 years ago

Help please! Thanks

Mathematics

2 answers:

mihalych1998 [28]3 years ago

7 0

Step-by-step explanation:

$\Delta ABC\cong\Delta PQR\\\\\begin{array}{ccc}\Delta&\to&\Delta\\A&\to&P\\B&\to&Q\\C&\to&R\end{array}\\\\\text{Therefore}\ \angle C\cong\angle R$

Grace [21]3 years ago

4 0

Answer:

Step-by-step explanation:

Apply the knowledge of CPCTC (corresponding parts of congruent triangles are congruent) to this

C and R are written last, and order is important, because they are congruent

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Marina86 [1]

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4 years ago

What is the solution to log_5 (10x-1)=log_5 (9x+7)

MArishka [77]

Answer: D

To solve the equation we proceed as follows:

log5(10x-1)=log5(9x+7)

canceling out log5 we get:

(10x-1)=(9x+7)

solving for x we get:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

If a and b are the measures of two first quadrant angles and sin a = 4/9 and sin b = 2/5 find sin(a+b).

frutty [35]

Answer:

$sin(a+b)=\frac{4\sqrt{21}+2\sqrt{65}}{45}$

Step-by-step explanation:

we are given

$sin(a)=\frac{4}{9}$

$sin(b)=\frac{2}{5}$

Firstly, we will draw triangle

we get

$cos(a)=\frac{\sqrt{65} }{9}$

$cos(b)=\frac{\sqrt{21} }{5}$

now, we can sue formula

$sin(a+b)=sin(a)cos(b)+cos(a)sin(b)$

now, we can plug values

$sin(a+b)=\frac{4}{9}\times \frac{\sqrt{21} }{5}+\frac{\sqrt{65} }{9}\times \frac{2}{5}$

now, we can simplify it

$sin(a+b)=\frac{4\sqrt{21}+2\sqrt{65}}{45}$

6 0

3 years ago

Pls help I will mark u as braniliest !!

Zepler [3.9K]

Answer:

CW, CT, MP, LW, MW

Step-by-step explanation:

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3 0

3 years ago

Help please it will mean so much thanks ❤️

____ [38]

Answer:

y = 14

Step-by-step explanation:

y = x^2 -5x

Let x =7

y = 7^2 -5*7

y = 49- 35

y = 14

5 0

3 years ago