The vertex is the high point of the curve, (2, 1). The vertex form of the equation for a parabola is
.. y = a*(x -h)^2 +k . . . . . . . for vertex = (h, k)
Using the vertex coordinates we read from the graph, the equation is
.. y = a*(x -2)^2 +1
We need to find the value of "a". We can do that by using any (x, y) value that we know (other than the vertex), for example (1, 0).
.. 0 = a*(1 -2)^2 +1
.. 0 = a*1 +1
.. -1 = a
Now we know the equation is
.. y = -(x -2)^2 +1
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If we like, we can expand it to
.. y = -(x^2 -4x +4) +1
.. y = -x^2 +4x -3
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An alternative approach would be to make use of the zeros. You can read the x-intercepts from the graph as x=1 and x=3. Then you can write the equation as
.. y = a*(x -1)*(x -3)
Once again, you need to find the value of "a" using some other point on the graph. The vertex (x, y) = (2, 1) is one such point. Subsituting those values, we get
.. 1 = a*(2 -1)*(2 -3) = a*1*-1 = -a
.. -1 = a
Then the equation of the graph can be written as
.. y = -(x -1)(x -3)
In expanded form, this is
.. y = -(x^2 -4x +3)
.. y = -x^2 +4x -3 . . . . . . same as above
In a system of equations ax + b = 0, a≠ 0, the equation x = -b/a is referred as a non-trivial solution.
<h3>What is a system of equations?</h3>
A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
The system Ax + b = 0 has the following solutions:
- The zeros, which is the trivial solution.
- x = -b/a, which is the non-trivial solution.
More can be learned about a system of equations at brainly.com/question/24342899
#SPJ1
Answer:
y=2x-8
or
f(x)=2x-8
Step-by-step explanation:
To write in slope-intercept form using this information, first use the point slope formula.
y-y1=m(x-x1)
m is slope.
y+4=2(x-2)
Use distributive property on the right side.
y+4=2x-4
Now, subtract 4 from both sides.
y+4-4=2x-4-4
y=2x-8
Written using function notation:
f(x)=2x-8
Hope this helps!
If not, I am sorry.
Answer:
Step-by-step explanation:
Common denominator: 18
-14/18 + 11/18
= -3/18
Reduce:
-1/6
A/2-b/3=1 solve for a, add b/3 to both sides
a/2=1+b/3 which is equal to
a/2=(3+b)/3 multiply both sides by 2
a=(6+2b)/3 now you can substitute this into 2a+3b giving you:
2(6+2b)/3 + 3b which is equal to
(12+4b+9b)/3
(13b+12)/3
