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Irina-Kira [14]
3 years ago
6

If mrs.hamm divides 7 pounds of potting soil equally into three flower pots,what is the weight of potting soil in one flower pot

?
Mathematics
1 answer:
blsea [12.9K]3 years ago
8 0

Answer:

The weight of potting soil in one flower pot = 2.33 pounds ( to 2 decimal places)

Step-by-step explanation:

If Mrs Hamm, divides 7 pounds of potting soil equally into three flower pots, it means that if the total available weight of potting soils were divided into three parts equally, each flower pot took a part, and this is calculated as shown below:

Total weight to be divided = 7 pounds

number of flower pots = 3

∴ weight of soil in each pot = (Total weight to be divided) ÷ (number of flower pots)

∴ weight of soil in each pot = 7 ÷ 3 = 2.33 pounds ( to 2 decimal places)

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F [ x ] = [ x - 3] [ x + 8 ]
bogdanovich [222]

Answer:

f [ x ] = [ x - 3] [ x + 8 ] = x^2 + 5x - 24

Step-by-step explanation:

f (x)=[ x - 3] [ x + 8 ]

x [ x + 8 ] -3[ x + 8 ]

x^2 + 8x - 3x - 24

x^2 + 5x - 24

8 0
3 years ago
Which of the following is the standard form of the equation 5x2 - 20x = 15?
Sophie [7]
It is C. The first part is raised to the 2nd power. so it goes first since that is the highest. then the -20x because variables are understood to the power of 1, while normal numbers are understood to the power of 0. so the order is highest to lowest (2,1,0)
4 0
3 years ago
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In a certain neighborhood, there's a sagging power line between two utility poles. The utility poles are 50 feet tall and 120 fe
e-lub [12.9K]
<h3>Answer:  33.75 feet</h3>

In fraction form, this value is equal to 135/4

33.75 ft is equivalent to 33 ft, 9 inches.

===============================================

Explanation:

Refer to the diagram below.

The key point to start with is point H, which is the vertex of the parabola.

Recall that vertex form is

y = a(x-h)^2 + k

What we'll do is plug in the vertex (h,k) = (60,30) which is the location of point H. We'll also plug in (0,45) which is the y intercept, aka the location of point C.

So,

y = a(x-h)^2 + k

y = a(x-60)^2 + 30 .... plug in vertex

45 = a(0-60)^2 + 30 .... plug in y intercept coordinates

45 = a(-60)^2 + 30

45 = a(3600) + 30

45 = 3600a + 30

45-30 = 3600a

3600a = 15

a = 15/3600

a = 1/240

This then means:

y = a(x-h)^2 + k

y = (1/240)(x-60)^2 + 30

This is the equation of our parabola. Plug in x = 30 to determine the height of point K

y = (1/240)(x-60)^2 + 30

y = (1/240)(30-60)^2 + 30

y = (1/240)(-30)^2 + 30

y = (1/240)(900) + 30

y = 15/4 + 30

y = 15/4 + 120/4

y = 135/4

y = 33.75

Therefore, the height of the power line, when it is 30 feet away from one of the poles, is 33.75 feet. This is the y coordinate of point K.

Side note: 33.75 ft = 33 ft + 0.75 ft = 33 ft + 12*0.75 in = 33 ft + 9 inches

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