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Irina-Kira [14]
3 years ago
6

If mrs.hamm divides 7 pounds of potting soil equally into three flower pots,what is the weight of potting soil in one flower pot

?
Mathematics
1 answer:
blsea [12.9K]3 years ago
8 0

Answer:

The weight of potting soil in one flower pot = 2.33 pounds ( to 2 decimal places)

Step-by-step explanation:

If Mrs Hamm, divides 7 pounds of potting soil equally into three flower pots, it means that if the total available weight of potting soils were divided into three parts equally, each flower pot took a part, and this is calculated as shown below:

Total weight to be divided = 7 pounds

number of flower pots = 3

∴ weight of soil in each pot = (Total weight to be divided) ÷ (number of flower pots)

∴ weight of soil in each pot = 7 ÷ 3 = 2.33 pounds ( to 2 decimal places)

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The best and most correct answer among the choices provided by your question is the third choice or letter C "<span>Multiplication Property of Equality"</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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1. Which words represent ADDITION<br> less than<br> sum<br> more than<br> times
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In the New York State daily lottery game, a sequence of 4 (not necessarily different) digits in the range of 0-9 is selected at
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50.40% probability that all 4 are different.

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A probability is the number of desired outcomes divided by the number of total outcomes.

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Whats the equation of the line that passes threw -4,4 and is parrell to the line y=1/2-4
vovangra [49]

Answer:

y=\frac{1}{2}x+6

Step-by-step explanation:

Given:

The equation of the known line is:

y=\frac{1}{2}x-4

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Now, since the two lines are parallel, their slopes must be equal.

Now, slope of the known line is the coefficient of 'x' which is \frac{1}{2}.

Therefore, the slope of the unknown line is also m=\frac{1}{2}

Now, for a line with slope 'm' and a point on it (x_1,y_1) is given as:

y-y_1=m(x-x_1)

Here, m=\frac{1}{2}, x_1=-4,y_1=4. Therefore,

y-4=\frac{1}{2}(x-(-4))\\\\y-4=\frac{1}{2}(x+4)\\\\y-4=\frac{1}{2}x+2\\\\y=\frac{1}{2}x+2+4\\\\y=\frac{1}{2}x+6

Hence, the equation of the unknown line is y=\frac{1}{2}x+6.

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4 years ago
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