Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer:
The sum of two numbers is 25. One of the numbers exceeds the other by 9. Find numbers
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the other number = x + 9
Let the number be x.
Sum of two numbers = 25
According to question, x + x + 9 = 25
⇒ 2x + 9 = 25
⇒ 2x = 25 - 9
⇒ 2x = 16
⇒ 2x/2 = 16/2
⇒ x = 8
Therefore, x + 9 = 8 + 9 = 17
Therefore, the two numbers are 8 and 17.
Hmmmmmm I think I know the answer to this
Answer:
Yes, (-3, -9) is a solution.
Step-by-step explanation:
y = 3x (-3,-9)
-9 = 3(-3)
-9 = -9
