2x-y=3 4x-y=3 How many system of equations do they have

Pls help me:) A-(4•7)^-4 B-1/28^2 C-7^-2/4^2 D-(4•7)^4

Sergio039 [100]

Answer:

$\frac{1}{(28)^{2} }$

Step-by-step explanation:

Step 1;

Write expression

$4^{-2} . 7^{-2\\\frac{\frac{1}{4^{-2} } }{y\frac{1}{7^{-2} } } }$

$\frac{1}{4^{2} .7^{2} }$

$\frac{1}{(4x7)^{2} }$

$\frac{1}{(28)^{2} }$

8 0

2 years ago

Pls help test due soon!

andreev551 [17]

3 years
15 = 250(0.06)
45/15 = 3

4 0

2 years ago

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Find the equation of the line which passes through the point (7,2) and is perpendicular to y=5x-2

MariettaO [177]

Answer:

$\displaystyle y=-\frac{1}{5}x+\frac{17}{5}$

Step-by-step explanation:

Equation of a line

A line can be represented by an equation of the form

$y=mx+b$

Where x is the independent variable, m is the slope of the line, b is the y-intercept and y is the dependent variable.

We need to find the equation of the line passing through the point (7,2) and is perpendicular to the line y=5x-2.

Two lines with slopes m1 and m2 are perpendicular if:

$m_1.m_2=-1$

The given line has a slope m1=5, thus the slope of our required line is:

$\displaystyle m_2=-\frac{1}{m_1}=-\frac{1}{5}$

The equation of the line now can be expressed as:

$\displaystyle y=-\frac{1}{5}x+b$

We need to find the value of b, which can be done by using the point (7,2):

$\displaystyle 2=-\frac{1}{5}*7+b$

Operating:

$\displaystyle 2=-\frac{7}{5}+b$

Multiplying by 5:

$10=-7+5b$

Operating:

$10+7=5b$

Solving for b:

$\displaystyle b=\frac{17}{5}$

The equation of the line is:

$\boxed{\displaystyle y=-\frac{1}{5}x+\frac{17}{5}}$

7 0

2 years ago

Combine. Express your answer in terms of the smaller unit. 3 L - 700 ml = ___ml

TEA [102]

The answer is 2300 ml.

7 0

2 years ago

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In your own words, explain why there is no solution to the following equation:| x-6|= -8 Also, knowing this, how does it help to

solniwko [45]

Answer:

Step-by-step explanation:

So the two lines before and after the expression means absolute value, or modulus of, knowing this, it means that the answer must always yield positive. So if x-6 is positive, it will stay positive, if x-6 is negative, it will turn positive, therefore it can never yield a negative value.

Now im assuming the second question is meant to be absolute value of x-5 is less than 0, because it makes no sense otherwise.

So now knowing that x-5 is always positive, or 0, but this inequality only wants less than 0, this means there are no solutions for the inequality.

5 0

2 years ago