Name a point that is (radical 2) away from (-1,5).

1 answer:

8 0

The questions asked to name a particular points that contains x and y coordinates.
 distance = (x -(-1))2 + (y -5)2 = 2
distance = (x +1))2 + (y -5)2 = 2
 => (√(2) -1,5)
 => (-1, 5 + √ (2)
 => (0, 4)
 => (0, 6)Thus, here are the lists of possible points. (0, 4) and (0, 6).

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$P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda$

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$=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599$

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$0.2599\times 18=4.6798$

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$P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr$