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Orlov [11]
2 years ago
10

2 ft

Mathematics
1 answer:
sdas [7]2 years ago
4 0

Answer:

88/7 ft = 12.6 ft (nearest tenth)

Step-by-step explanation:

Circumference of a circle = 2\pir

<u>Radius of inner circle</u>

Given:

  • circumference of inner circle = 22ft
  • \pi = 22/7

⇒ 22 = 2 x (22/7) x r

⇒ r = 3.5

So the radius of the inner circle is 3.5 ft

<u>Radius of outer circle</u>

If the distance between the inner circle and the outer circle is 2 ft, then the radius of the outer circle = 3.5 + 2 = 5.5

<u>Circumference of outer circle</u>

Therefore, circumference of outer circle:

=  2 x (22/7) x 5.5

= 242/7 ft

<u>Difference between circumferences</u>

Difference = outer circle circumference - inner circle circumference

                  = 242/7 - 22

                  = 88/7 ft

                  = 12.6 ft (nearest tenth)

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Answer:

The rule of dilation is P'(x,y) = 3\cdot P(x,y).

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Step-by-step explanation:

From Linear Algebra, we define the dilation by the following definition:

P'(x,y) = O(x,y) + k\cdot[P(x,y)-O(x,y)] (1)

Where:

O(x,y) - Center of dilation, dimensionless.

k - Scale factor, dimensionless.

P(x,y) - Original point, dimensionless.

P'(x,y) - Dilated point, dimensionless.

If we know that O(x,y) = (0,0), k = 3, A(x,y) = (-7,-6), B(x,y) = (-5,-2) and C(x,y) =(-1,-5), then dilated points of triangle ABC are, respectively:

A'(x,y) = O(x,y) + k\cdot [A(x,y)-O(x,y)] (2)

A'(x,y) = (0,0) + 3\cdot [(-7,-6)-(0,0)]

A'(x,y) = (-21, -18)

B'(x,y) = O(x,y) + k\cdot [B(x,y)-O(x,y)] (3)

B'(x,y) = (0,0) + 3\cdot [(-5,-2)-(0,0)]

B'(x,y) = (-15,-10)

C'(x,y) = O(x,y) + k\cdot [C(x,y)-O(x,y)] (4)

C'(x,y) = (0,0) +3\cdot [(-1,-5)-(0,0)]

C'(x,y) = (-3,-15)

The rule of dilation is:

P'(x,y) = 3\cdot P(x,y) (5)

The vertices of the dilated triangle are A'(x,y) = (-21, -18), B'(x,y) = (-15,-10) and C'(x,y) = (-3,-15), respectively.

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