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Blababa [14]
2 years ago
12

PLEASE HELP WILL MARK BRAINLIEST FOR BEST ANSWER If you reflect (-2, -8) across both axes, which quadrant will it be in? Justify

your reasoning. Please no links or files
Mathematics
1 answer:
Tpy6a [65]2 years ago
4 0

Answer:

  I

Step-by-step explanation:

Reflecting the point across both axes changes the signs of both coordinates. The reflected point will be (2, 8). Both coordinates are positive for points in Quadrant I.

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Divide £42 in a ratio of 4:6
NISA [10]
4:6
4+6 =10

£42 / 10 = £4.20

£4.20 * 4 = £16.80
£4.20 * 6 = £25.20

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3 0
3 years ago
Please solve this for me using substitution
Vinvika [58]

<h2> <u>Explanation</u><u>:</u></h2>

\bf \underline{★Given-} \\

\textsf{4x + 5y = 8};

\textsf{5x + 4y = 12}

\bf \underline{★To\: find-} \\

\textsf{the value of x and y in equation?}

\bf \underline{★Solution-} \\

\sf \leadsto 4x + 5y = 8 - - - (i)

\sf \leadsto 5x + 4y = 12 - - - (ii)

By first equation,

\sf \leadsto 4x + 5y = 8

\sf \leadsto 4x = 8 - 5y

\sf \leadsto x = \dfrac{8 - 5y}{4}

\textsf{Now, we can find the original value of Y.}\\

\sf \leadsto 5x + 4y = 12

\sf \leadsto 5 \bigg( \dfrac{8 - 5y}{4} \bigg) + 4y = 12

\sf \leadsto \dfrac{40 - 25y}{4} + 4y = 12

\sf \leadsto \dfrac{40 - 25y + 16y}{4} = 12

\sf \leadsto \dfrac{40 - 9y}{4} = 12

\sf \leadsto 40 - 9y = 12(4)

\sf \leadsto 40 - 9y = 48

\sf \leadsto -9y = 48 - 40

\sf \leadsto -9y =  8

\sf \leadsto y = \dfrac{ -8}{9}

\textsf{Now, we can find the original value of X.}\\

\sf \leadsto 4x + 5y = 8

\sf \leadsto  4x + 5 \bigg( \dfrac{ -8}{9} \bigg) = 8

\sf \leadsto 4x - \dfrac{40}{9} = 8

\sf \leadsto \dfrac{36x - 40}{9} = 8

\sf \leadsto 36x - 40 = 8(9)

\sf \leadsto 36x - 40 = 72

\sf \leadsto 36x = 72 + 40

\sf \leadsto 36x = 112

\sf \leadsto x = \dfrac{112}{36}

\underline{\textsf{Answer-}}\\

Therefore, the values of x and y are -8/9 and 112/36 respectively.

6 0
2 years ago
I need help asap i need to answer it in 3 min plzzzzzz help
Natali [406]

Answer:

XZ = 9 * 4= 36

BC = 48 / 4 = 12

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