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scoray [572]
2 years ago
6

I need help on this, if anyone knows how to do this can you help me out pls

Mathematics
1 answer:
ASHA 777 [7]2 years ago
6 0
<h3>Answer:  (3, 0)</h3>

=================================================

Explanation:

Let's isolate x in the first equation.

x-2y = 3

x = 3+2y

Then we'll plug this into the second equation

Afterwards, solve for y.

2x + 4y = 6

2(3+2y)+4y = 6

6+4y+4y = 6

8y+6 = 6

8y = 6-6

8y = 0

y = 0/8

y = 0

Use this to find x.

x = 3+2y

x = 3+2(0)

x = 3

The solution is therefore (x,y) = (3, 0)

If you were to graph both lines, then they would intersect at the location (3,0).

-----------------------------

Checking the answer:

Plug x = 3 and y = 0 into the first equation.

x-2y = 3

3-2(0) = 3

3 - 0 = 3

3 = 3 that works

Repeat for the other equation

2x+4y = 6

2(3) + 4(0) = 6

6 + 0 = 6

6 = 6 that works as well

Both equations are true when (x,y) = (3,0).

The solution is confirmed.

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Find the slope of the line passing through the points (5,7) and (-4,2).
Andre45 [30]

Your answer is A!

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3 years ago
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If QS bisects PQT, SQT=(8x- 25),PQT=(9x+34), and SQR=112, find each measure.
Goryan [66]

The values of the angles are; x = 12°, m∠PQS = 71°, m∠PQT = 142° and m∠TQR = 41°

<h3>What are the measure of the each angle?</h3>

The required angles; x, m∠PQS, m∠PQT, and m∠TQR

The given parameters are bisects ∠PQT

m∠SQT = (8·x - 25)°

m∠PQT = (9·x + 34)°

m∠SQR = 112°

We have;

m∠PQT = m∠SQT + m∠PQS (Angle addition postulate)

m∠SQT ≅ m∠PQS (Angles formed by angle bisector are congruent)

m∠SQT = m∠PQS  by Definition of congruency

m∠PQT = 2 × m∠SQT

Therefore;

(9·x + 34)° = 2 × (8·x - 25)° = (16·x - 50)°

Collecting like terms gives:

(34 + 50)° = 16·x - 9·x = 7·x

7·x = 84°

x = 84°/7 = 12°

x = 12°

m∠SQT = (8·x - 25)°

Therefore;

m∠SQT = (8 × 12 - 25)° = 71°

m∠SQT = 71°

m∠PQT = 2 × m∠SQT

∴ m∠PQT = 2 × 71° = 142°

m∠PQT = 142°

m∠PQS = m∠SQT (Angles formed by the same bisector )

∴ m∠PQS = m∠SQT = 71°

m∠PQS = 71°

m∠SQR = m∠SQT + m∠TQR (Angle addition postulate)

m∠SQT = 71°

∴  m∠SQR = 112° = 71° + m∠TQR

m∠TQR = 112° - 71° = 41°

m∠TQR = 41°

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4 0
1 year ago
2.) Find the measure of exterior angle X:
Oxana [17]
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try 110 , sorry if that’s wrong
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Seven people are in an elevator which stops at ten floors. In how many ways can they get off the elevator?
zlopas [31]

The number of ways people can get off the elevator is 604800 ways.

In this question,

Number of people, n = 7

Number of floors, r = 10

The first person can leave elevator in one of 10 ways. Then second person has to choose from one of remaining 9 floors. Then third person in 8, fourth in 7 ways and so on.

Number of ways people can get off the elevator can be calculated as

⇒ nP_r=\frac{n!}{(n-r)!}

⇒ 10P_{7}=\frac{10!}{(10-7)!}

⇒ 10P_{7}=\frac{10!}{(3)!}

⇒ 10P_{7}=\frac{(10)(9)(8)(7)(6)(5)(4)3!}{(3)!}

⇒ 10P_{7}=(10)(9)(8)(7)(6)(5)(4)

⇒ 604800 ways.

Hence we can conclude that the number of ways people can get off the elevator is 604800 ways.

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QveST [7]

Answer:

to be entirely honest i do not know

Step-by-step explanation:

5 0
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