Question

I need help on this, if anyone knows how to do this can you help me out pls

Answer 1

Answer:  (3, 0)

=================================================

Explanation:

Let's isolate x in the first equation.

x-2y = 3

x = 3+2y

Then we'll plug this into the second equation

Afterwards, solve for y.

2x + 4y = 6

2(3+2y)+4y = 6

6+4y+4y = 6

8y+6 = 6

8y = 6-6

8y = 0

y = 0/8

y = 0

Use this to find x.

x = 3+2y

x = 3+2(0)

x = 3

The solution is therefore (x,y) = (3, 0)

If you were to graph both lines, then they would intersect at the location (3,0).

-----------------------------

Checking the answer:

Plug x = 3 and y = 0 into the first equation.

x-2y = 3

3-2(0) = 3

3 - 0 = 3

3 = 3 that works

Repeat for the other equation

2x+4y = 6

2(3) + 4(0) = 6

6 + 0 = 6

6 = 6 that works as well

Both equations are true when (x,y) = (3,0).

The solution is confirmed.