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BabaBlast [244]
3 years ago
7

What is the answer to negative 16v+v=3v+2v

Mathematics
1 answer:
kap26 [50]3 years ago
8 0
I think the answer would be negative 3
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Use calculus to find the first order conditions. Use solver then to solve the first order conditions. Show your work for the fir
DaniilM [7]

The values of x and y are 70/22 and 30/22 respectively by using the first-order condition of differential calculus.

<h3>What is the first-order condition in differential calculus?</h3>

A first-order differential equation is represented by the equation \mathbf{ \dfrac{dy}{dx} =f (x,y) }with 2 variables x & y, including its function f(x,y) specified on a xy-plane.

Given that:

\mathbf{f(x,y) =-22x^2+22xy-11y^2+110x-40y-23}

Let us first differentiate the above equation with respect to x, we have:

\mathbf{\dfrac{\partial f(x,y) }{\partial x}  = -44x +22y -0+110-0-0=0}

\mathbf{\implies  -44x +22y+110=0}        (multiply by -1)

44x - 22y = 110    ------ (equation 1)

Now, differentiating with respect to y, we have:

\mathbf{\dfrac{\partial f(x,y) }{\partial y}  =0 +22x-22y +0-40-0=0}

\mathbf{\implies 22x-22y -40=0}

22x - 22y = 40      ----- (equation 2)

Now, we have a system of equations:

44x - 22y = 110

-                      ---- ( subtracting equation 2 from 1; elimination method)

<u> 22x - 22y = 40  </u>

<u>22x    + 0  = 70    </u>

<u />

x = 70/22

Replacing the value of x into equation (1), we have:

44x - 22y = 110

44(70/22) - 22y = 110

140 - 22y = 110

140 - 110 = 22y

30 = 22y

y = 30/22

Learn more about the first-order conditions in differential calculus here;

brainly.com/question/14528981

#SPJ1

4 0
2 years ago
Doug left $3 as a tip on a lunch bill of $14.
Svetllana [295]

Answer:

a)

Step-by-step explanation:

5 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST
Dmitry_Shevchenko [17]

Answer:

I believe the answer is (A)

*Substituting the x and y values from the table into the equation(A) will balance the right side of the equation to the left side of the equation.

7 0
2 years ago
<img src="https://tex.z-dn.net/?f=y%20%2B%205%20%3D%20x%20%7B%3F%7D%5E%7B2%7D%20" id="TexFormula1" title="y + 5 = x {?}^{2} " al
zimovet [89]
What is your question?
3 0
3 years ago
Solve each system by substitution 14x-35=7y<br> -25-6x=5y
Savatey [412]

Answer:

<em>The solution of the system will be:  x=0, y= -5</em>

Step-by-step explanation:

The given system of equation is......

14x-35=7y ...................................(1)\\ \\ -25-6x=5y..................................(2)

First, solving for y in the equation (1) ........

\frac{14x-35}{7}= \frac{7y}{7} \\ \\ y=2x-5

Now, substituting this y=2x-5 into equation (2), we will get........

-25-6x=5(2x-5)\\ \\ -25-6x=10x-25\\ \\ -25+25=10x+6x\\ \\ 0=16x\\ \\ x=\frac{0}{16}=0

Plugging x=0 into y=2x-5, we will get.......

y=2(0)-5= -5

So, the solution of the system will be:  x=0, y= -5

5 0
3 years ago
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