- Endothermic reaction means the reactant side takes heat from surrounding and get decomposed i.e ∆H=-ve
- If the equation is exothermic then it means the reactant is happy to decompose .But it's not as it's endothermic
Now
- HgO is Omitted from our solution option.
Hg is a atom so no bonds hence no bond strength occurs.
- O_2 is a molecule and so it's our answer .
The KE can be solve using the formula:
ke = 0.5 mv^2
where m is the mass of the object
v is the velocity
ke = 0.5 ( 2 kg ) ( 5 m/s)^2
ke = 25 J
the GPE can be solved using the formula:
GPE = mgh
where m is the mass
g is the acceleration due to gravity ( 9.81 m/s^2)
h is the height
GPE = ( 4 kg)(9.81 m/s^2)( 40 m)
GPE = 392.4 J
Answer:
The pressureof the secondone is 2.5 atm
Explanation:
hope this helps
Explanation:
Formula to calculate specific rotation is as follows.
Specific rotation (![[\alpha]](https://tex.z-dn.net/?f=%5B%5Calpha%5D)
) = 
where, 
= observed rotation
c = concentration in g/ml
l = path length in dm
It is given that,
c = 
= 0.02 g/ml
l = 20 cm = 2 dm (as 1 dm = 10 cm)
Therefore, calculate the specific rotation as follows.
Specific rotation () =
= 
= 
Thus, we can conclude that the specific rotation of this compound is .
