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kirill [66]
2 years ago
6

If the reaction 2HgO --> 2Hg + O2 is endothermic, which bonds are the strongest?

Chemistry
1 answer:
Alika [10]2 years ago
3 0
  • Endothermic reaction means the reactant side takes heat from surrounding and get decomposed i.e ∆H=-ve
  • If the equation is exothermic then it means the reactant is happy to decompose .But it's not as it's endothermic

Now

  • HgO is Omitted from our solution option.

Hg is a atom so no bonds hence no bond strength occurs.

  • O_2 is a molecule and so it's our answer .
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If scientists had tried to repeat thomosons experiment and found that they could not would thomosons cocnclusion still have been
lesantik [10]

Answer:

No

Explanation:

The conclusions from Thomoson's claims would be invalid if his experiment could not be replicated.

<em>One of the attributes of a valid experiment in science is replication. That is, an experiment must be repeatable with similar outcomes under similar conditions as the original experiment when independently performed by another scientist. Once an experiment cannot be replicated, the outcomes of such an experiment become invalid in science.</em>

Hence, <u>Thomoson's conclusion would be invalid if his experiment could not be replicated. </u>

5 0
3 years ago
8. which change in state is associated with the heat of vaporization,
rewona [7]
The answer is 2, liquid to vapor because vaporization is the process of liquids to vapors.
8 0
3 years ago
1. A gas sample at a pressure of 5.00 atm has a volume of 3.00 L. If the gas pressure is changed to 760 mm Hg, what volume will
tatyana61 [14]

Answer:

V₂ =  15.00 atm

Explanation:

Given data:

Initial pressure = 5.00 atm

Initial volume = 3.00 L

Final pressure = 760 mmHg ( 760/760 = 1 atm)

Final volume = ?

Solution:

P₁V₁ = P₂V₂

V₂ = P₁V₁ /  P₂

V₂ =  5.00 atm × 3.00 L / 1 atm

V₂ =  15.00 atm

8 0
3 years ago
What is protein denaturation​
Schach [20]

Answer:

Denaturation is a process in which proteins or nucleic acids lose the quaternary structure, tertiary structure, and secondary structure which is present in their native state, by application of some

Explanation:

6 0
2 years ago
A tank of gas is found to exert 8.6 atm at 38°C. What would be the required
Vesna [10]

Answer:

36.2 K

Explanation:

Step 1: Given data

  • Initial pressure of the gas (P₁): 8.6 atm
  • Initial temperature of the gas (T₁): 38°C
  • Final pressure of the gas (P₂): 1.0 atm (standard pressure)
  • Final temperature of the gas (T₂): ?

Step 2: Convert T₁ to Kelvin

We will use the following expression.

K = °C +273.15

K = 38 °C +273.15 = 311 K

Step 3: Calculate T₂

We will use Gay Lussac's law.

P₁/T₁ = P₂/T₂

T₂ = P₂ × T₁/P₁

T₂ = 1.0 atm × 311 K/8.6 atm = 36.2 K

6 0
2 years ago
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