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KatRina [158]
3 years ago
12

Someone please helppppppp

Chemistry
1 answer:
antiseptic1488 [7]3 years ago
5 0

Answer:

a

Explanation:

because. it is more bigger

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Parents should avoid sharing their own mistakes with children. True/false
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Read 2 more answers
How would the pH value of an aqueous solution change, when the hydronium ion concentration is increased by a factor of 10?
Anna71 [15]

Answer:

Increasing H⁺ by 10x => pH decreases by 1 unit

Explanation:

In general, adding H⁺ ions to any aqueous solution ALWAYS causes pH values to fall ( decrease ). Just as adding OH⁻ ions to an aqueous solution causes pH values to rise ( increase ).

Here's a simple calculation demonstrating this...

Given 0.01M HCl(aq) => 0.01M H⁺(aq) + Cl⁻(aq) => pH = -log(0.01) = 2.00

Increase [H⁺] by 10x => 0.10M H⁺(aq) => pH = -log[H⁺] = -log(0.10) = 1.00

Solution with higher H⁺ concentration shows <u>pH decreasing by 1 unit.</u>

______________________________________________________-

Just to support the above statement about adding OH⁻ ions showing an increase in pH values, the following is also provided FYI ..

Given 0.01M NaOH(aq) => 0.01M OH⁻(aq) + Na⁺(aq) => pOH = -log(0.01) = 2.00 => pH = 14 - pOH = 14 - 2 = 12

Increase [OH⁻] by 10x => 0.10M OH⁻(aq) => pOH = -log[OH⁻] = -log(0.10) = 1.00 => pH = 14 - pOH = 14 - 1 = 13

Increasing [OH⁻] by 10x => <u>increasing pH by 1 unit. </u>

Solution with higher H⁺ concentration shows pH decreasing by 1 unit.

______________________________________________________

Remember, for <u>any</u> aqueous solution ...

=> Adding H⁺   => always decreases pH

=> Adding OH⁻ => always increases pH

4 0
3 years ago
What evidence of chemical reaction will be observed based on this chemical reaction?
Elis [28]
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4 years ago
A 1.0 L sample of an aqueous solution contains 0.10 mol of NaCl and 0.10 mol of CaCl2. What is the minimum number of moles of Ag
Annette [7]

Answer:

The answer to your question is: 0.3 moles of AgNO₃

Explanation:

1.0 L sample

0.1 mol of NaCl

0.1 mol of CaCl₂

AgNO₃ = ? moles

Reactions

               NaCl + AgNO₃ ⇒ AgCl + NaNO₃

Then                1 NaCl mol ---------------  1 AgNO₃

                     0.1 mol           --------------    x

             x = 0.1 moles of AgNO₃ needed

             

              CaCl₂ + 2 AgNO₃ ⇒ 2 AgCl + Ca(NO₃)₂

Then                 1 mol of CaCl₂ ------------- 2 moles of AgNO₃

                       0.1 mol              -------------      x

            x = 0.2 moles of AgNO₃

Total moles of AgNO₃ = 0.1 + 0.2 = 0.3

5 0
3 years ago
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