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DaniilM [7]
2 years ago
12

Braden jumped 9 5 16 feet in the long jump. Jordan jumped 8 7 8 feet. How much farther did Braden jump than Jordan?

Mathematics
2 answers:
lakkis [162]2 years ago
8 0

Answer:

Braden jump \frac{7}{16} feet higher than Jordan.

Step-by-step explanation:

distance between jumps: Branden's jump - Jordan's jump

Here Braden's jump is 9 \frac{5}{16} and Jordan's jump is 8 \frac{7}{8}

Distance between jump's:

9 \frac{5}{16}  -  8 \frac{7}{8}

\frac{149}{16}  - \frac{71}{8}

\frac{149}{16}  - \frac{142}{16}

\frac{149-142}{16}

\frac{7}{16}

Braden jump \frac{7}{16} feet higher than Jordan.

lesantik [10]2 years ago
8 0

First you want both of the denominators to be the same.

You can multiply \frac{7}{8} \times  2 to get \frac{14}{16}

So the two values are 9\frac{5}{16}and 8\frac{14}{16}

When you subtract both values you get the answer \frac{7}{16}

Answer : \frac{7}{16}

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Answer:

Relation between V and c is represented as:

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When c is halved, V becomes \frac{1}{8} of its initial value.

Step-by-step explanation:

Height of cylinder = Radius of cylinder = c

Volume of cylinder = V

As per formula:

V = \pi r^{2} h

Where r is the radius of cylinder and

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Putting r = h =c

V = \pi c^{2} \times c\\\Rightarrow V = \pi c^{3} ......(1)

The values of c is halved:

Using equation (1), New volume:

V' = \pi (\dfrac{c}{2})^3\\\Rightarrow \dfrac{1}{8} \pi c^{3}

By equation (1), putting \pi \times c^{3}  = V

V' = \dfrac{1}{8} \times V

So, when c is halved, V becomes \frac{1}{8} of its initial value.

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Step-by-step explanation:

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Together two ferries can transport a day's cargo in 7 hours. The larger ferry can transport cargo three times faster than the sm
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Answer:

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Step-by-step explanation:

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