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DaniilM [7]
2 years ago
12

Braden jumped 9 5 16 feet in the long jump. Jordan jumped 8 7 8 feet. How much farther did Braden jump than Jordan?

Mathematics
2 answers:
lakkis [162]2 years ago
8 0

Answer:

Braden jump \frac{7}{16} feet higher than Jordan.

Step-by-step explanation:

distance between jumps: Branden's jump - Jordan's jump

Here Braden's jump is 9 \frac{5}{16} and Jordan's jump is 8 \frac{7}{8}

Distance between jump's:

9 \frac{5}{16}  -  8 \frac{7}{8}

\frac{149}{16}  - \frac{71}{8}

\frac{149}{16}  - \frac{142}{16}

\frac{149-142}{16}

\frac{7}{16}

Braden jump \frac{7}{16} feet higher than Jordan.

lesantik [10]2 years ago
8 0

First you want both of the denominators to be the same.

You can multiply \frac{7}{8} \times  2 to get \frac{14}{16}

So the two values are 9\frac{5}{16}and 8\frac{14}{16}

When you subtract both values you get the answer \frac{7}{16}

Answer : \frac{7}{16}

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Answer:

Actual                                      2/3

30 inch. by 12 inch               240 inch²

30 inch. by 18 inch               360 inch²

12 inch. by 15 inch                  120inch²

18 inch. by 15 inch                 180inch²

Step-by-step explanation:

The answers are given in the same line .

Actual                                                      1/3                          2/3

30 inch. by 12 inch                                120 inch²                 240 inch²

30 inch. by 18 inch                                180 inch²                 360 inch²

12 inch. by 15 inch                                  60 inch²                  120inch²

18 inch. by 15 inch                                90 inch²                    180inch²

We  find the areas and multiply by 2/3 to get the answers

30 * 12= 360 inch²

2/3 * 360 = 240 inch²

30 * 18= 540 inch²

2/3 * 540 = 360inch²

12 * 15= 180 inch²

2/3 * 180 = 120 inch²

18 * 15= 270 inch²

2/3 * 270 = 180inch²

3 0
2 years ago
a motorboat travels 456 km in 8 hours going upstream and 783 km in 9 hours going downstream. what is the rate of the boat in sti
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\begin{gathered} \text{Let;s assume the sp}e\text{d of boat in still water is x.} \\ And\text{ the spe}ed\text{ of stream is y.} \\ For\text{ upstream,} \\ (x-y)\times8=456 \\ x-y=57\ldots(1)_{} \\ (x+y)\times9=783 \\ x+y=87 \\ x=87-y\ldots(2) \\ \text{Now, substitute the value of x in the equation (1).} \\ 87-y-y=57 \\ -2y=57-87 \\ 2y=30 \\ y=15\text{ km/hours (rate of current)} \\ \text{Substitute the value of y in the equation (2).} \\ x=87-15 \\ x=72\text{ km/hours (boat in still water)} \end{gathered}

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1 year ago
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Step-by-step explanation:

2x+3=-7

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