Answer:
Suppose the closest point is at p=(x0,y0), and set q=(−2,−3). Then the tangent to the parabola at p is perpendicular to ℓ, the line through p,q. and we end up numerically computing the roots from here.
The value of 1/6 is less than the value of4\5.
So, the answer is < .
Answer: 0
Step-by-step explanation:
Since m is with x, you don't need to care about y
We would get 2x - 6x + 4x = mx
0x = mx
m is 0
radx-5=y.....(y+5)^2=x...(x+5)^2 a.or.b
Sub-greater radical equals 0 /d
7/9
