Answer:
146.41
Step-by-step explanation:
third order determinant = determinant of 3×3 matrix A
given ∣A∣=11
det (cofactor matrix of A) =set (transpare of cofactor amtrix of A) (transpare does not change the det)
=det(adjacent of A)
{det (cofactor matrix of A)} ^2 = {det (adjacent of A)}
^2
(Using for an n×n det (cofactor matrix of A)=det (A)^n−1
)
we get
det (cofactor matrix of A)^2 = {det(A) ^3−1
}^2
=(11)^2×2 = 11^4
=146.41
Answer:
The expression would give the probability that one marble is yellow and the other marble is red is,
![P(Y\cdot R\ And\ R\cdot Y)=P(Y)P(R)+P(R)P(Y)](https://tex.z-dn.net/?f=P%28Y%5Ccdot%20R%5C%20And%5C%20R%5Ccdot%20Y%29%3DP%28Y%29P%28R%29%2BP%28R%29P%28Y%29)
Step-by-step explanation:
A bag contains eight yellow marbles, nine green marbles, three purple marbles, and five red marbles. So in total there are 25 marbles.
Hence,
Probability of getting yellow ball = ![P(Y)=\dfrac{8}{25}](https://tex.z-dn.net/?f=P%28Y%29%3D%5Cdfrac%7B8%7D%7B25%7D)
Probability of getting red ball = ![P(R)=\dfrac{5}{25}](https://tex.z-dn.net/?f=P%28R%29%3D%5Cdfrac%7B5%7D%7B25%7D)
Probability that one marble is yellow and the other marble is red is,
![P(Y\cdot R\ And\ R\cdot Y)=P(Y)P(R)+P(R)P(Y)=\dfrac{8}{25}\cdot \dfrac{5}{25}+\dfrac{5}{25}\cdot \dfrac{8}{25}=0.128](https://tex.z-dn.net/?f=P%28Y%5Ccdot%20R%5C%20And%5C%20R%5Ccdot%20Y%29%3DP%28Y%29P%28R%29%2BP%28R%29P%28Y%29%3D%5Cdfrac%7B8%7D%7B25%7D%5Ccdot%20%5Cdfrac%7B5%7D%7B25%7D%2B%5Cdfrac%7B5%7D%7B25%7D%5Ccdot%20%5Cdfrac%7B8%7D%7B25%7D%3D0.128)
Answer:
A
Step-by-step explanation:
![\frac{4}{5} + \frac{2}{5} = \frac{6}{5} \\Simple make it improper, resulting in answer A](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B5%7D%20%2B%20%5Cfrac%7B2%7D%7B5%7D%20%3D%20%5Cfrac%7B6%7D%7B5%7D%20%5C%5CSimple%20make%20it%20improper%2C%20resulting%20in%20answer%20A)
Hope this helps!
36 + 16 = 52
36 - 16 = 20
So 36 and 16 are the numbers
I think you would just have to find the square roots