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worty [1.4K]
3 years ago
6

Which transformations would affect the starting point of a square root function?

Mathematics
1 answer:
lesya692 [45]3 years ago
6 0

Answer:

There are at least two transformations that would affect the starting point of a square root: (i) <em>Horizontal translation</em>, (ii) <em>Vertical translation</em>.

Step-by-step explanation:

Let the square be represented by the following function:

f(x) = \sqrt{x},\,\forall \,x \ge 0 (1)

Which means that function has only valid solutions for every element of x greater or equal to 0. In particular, the starting point is x = 0.

We can change the starting point of this function by horizontal translation, which is defined below:

g(x) = f(x - a), \,\forall \,x \ge a (2)

In other words, we create the resulting function:

g(x) = \sqrt{x-a}, \,\forall\,x \ge a (3)

Another, possibility is using a vertical translation, whose definition is defined below:

h(x) = f(x)+c,\,\forall \,x \ge 0 (4)

In other words, we create the following function:

h(x) = \sqrt{x} +c (5)

Hence, there are at least two transformations that would affect the starting point of a square root: (i) <em>Horizontal translation</em>, (ii) <em>Vertical translation</em>.

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Which equation has exactly one solution in common with the equation y=6x-2?
GalinKa [24]

Answer:

A. 18x - 3y = 6

Step-by-step explanation:

By taking 3 common from the terms 18x and 3y we get,

3 (6x-3y) = 6

or, 6x - y = 6/3

or, 6x - y = 2

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The equation becomes,

y = 6x - 2

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A group of children 6 to 10 years old were asked how many video games they owned. The scatter plot shows the results. What is th
jolli1 [7]

The range of the video games owned for the cluster is between 8 to 10.

Given

A group of children 6 to 10 years old were asked how many video games they owned.

The scatter plot shows the results.

<h3>What is the range?</h3>

The range is the difference between the lowest and highest numbers in a data set.

The range of video games owned for the cluster is 8 to 10.

Therefore,

The range of the video games owned for the cluster is;

\rm Range = Highest \ value - lowest \ value\\\\Range=10-8\\\\Range=2

Hence, the range of the video games owned for the cluster is between 8 to 10.

To know more about Range click the link given below.

brainly.com/question/8041076

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2 years ago
You have six trophies to arrange on the top shelf of the bookcase how many ways are there to arrange the trophies
e-lub [12.9K]

Answer:

So, we can do it in 720 ways.

Step-by-step explanation:

We have been given total of six trophies to arrange in the top shelf of the bookcase  

If we need to arrange n things in different ways we can do it in n! ways

Similarly, Here we will do it in 6! ways

n!=n(n-1)(n-2).....1

So, 6!=6 x 5 x 4 x 3 x 2 x 1=720

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3 years ago
If Upper X overbar equals 62​, Upper S equals 8​, and n equals 36​, and assuming that the population is normally​ distributed, c
marishachu [46]

Answer:

The 99% confidence interval would be given by (58.373;65.627)    

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=62 represent the sample mean

\mu population mean (variable of interest)

s=8 represent the sample standard deviation

n=36 represent the sample size  

Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=36-1=35

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that t_{\alpha/2}=2.72

Now we have everything in order to replace into formula (1):

62-2.72\frac{8}{\sqrt{36}}=58.373    

62+2.72\frac{8}{\sqrt{36}}=65.627    

So on this case the 99% confidence interval would be given by (58.373;65.627)    

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

3 0
3 years ago
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