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3 years ago

7

The owner of a garden center pays $12 for each birdbath. She sells them for 55% more than she paid. Decide whether each expressi

on represents the selling price for b birdbaths.

1 answer:

IRISSAK [1]3 years ago

3 0

For this case, the first thing we should do is define a variable.

We have then:

<em>b: number of birdbaths </em>

The cost of b birdbaths is given by:

$12b$

She sells them for 55% more than she paid. Therefore, the sale price is given by:

$12b + 0.55 (12b)$

Rewriting we have:

$1.55 (12b)$

Answer:

the selling price for b birdbaths is:

$1.55 (12b)$

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a tennis ball machine serves a ball vertically into the air from a height of 2 feet, with an intial speed of 130 feet per second

Dvinal [7]

For this case, the first thing to do is write the equation of moving the ball.
We have then:
h (t) = - 16t ^ 2 + 130t + 2
Deriving we have:
h '(t) = - 32t + 130
We match zero:
-32t + 130 = 0
We cleared t:
t = 130/32
t = 4.0625 s
We evaluate the value of t = 4.0625 s in the equation of motion:
h (4.0625) = - 16 * (4.0625) ^ 2 + 130 * (4.0625) + 2
h (4.0625) = 266.0625 feet
Answer:
The maximum height, in feet, the ball will attain is:
h (4.0625) = 266.0625 feet

4 0

3 years ago

Can someone help me Determine the intercepts of the line.

slavikrds [6]

Greetings!

To find the y-intercept, we can arrange the equation in slope y-intercept form:
$y=mx+b$

Rearrange:
$y+1=3(x-4)$

$y+1=3x-12$

$y=3x-13$

The y-intercept is: -13
$\boxed{(0,-13)}$

To find the x-intercept, we can input the value <<0>> in the place of y, as every x-intercept only occurs when y=0:
$(0)=3x-13$

Solve for x:
$0=3x-13$

$13=3x$

$\frac{13}{3}= \frac{3x}{3}$

$x=\frac{13}{3}$

The x-intercept is: $\frac{13}{3}$
$\boxed{(\frac{13}{3},0)}$

I hope this helped!
-Benjamin

5 0

3 years ago

Volume of cuboid is 343 length of edge cube

laiz [17]

Length of the cube = 7
Working:
Cube root of 343 =7
(or)
7^3=7*7*7=343

6 0

2 years ago

Please help me! I'll give u extra points

o-na [289]

Answer:

3

Step-by-step explanation:

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2 years ago

Calculate to the nearest 1/10th meter the length of the side of a 7th, 12th, and 30th hectare square plot.

Tems11 [23]

Answer and explanation:

To find : Calculate to the nearest 1/10th meter the length of the side of a 7th, 12th, and 30th hectare square plot.

Solution :

The area of the square is given by,

$A=s^2$ where s is the side length.

We know, $1 \text{ hectare}=10,000\ m^2$

1) The area of square plot is 7 hectare.

Area in meter square is $A=7\times 10000=70000\ m^2$

Substitute the value in the formula,

$70000=s^2$

$\sqrt{70000}=s$

$264.57=s$

Side nearest to 1/10th meter is 264.8 meter.

2) The area of square plot is 12 hectare.

Area in meter square is $A=12\times 10000=120000\ m^2$

Substitute the value in the formula,

$120000=s^2$

$\sqrt{120000}=s$

$346.41=s$

Side nearest to 1/10th meter is 346.4 meter.

3) The area of square plot is 30 hectare.

Area in meter square is $A=30\times 10000=300000\ m^2$

Substitute the value in the formula,

$300000=s^2$

$\sqrt{300000}=s$

$547.72=s$

Side nearest to 1/10th meter is 547.7 meter.

5 0

2 years ago