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2 years ago

1/5 and 5/6 what number could be a common denominator for these two fractions:

Mathematics

1 answer:

Likurg_2 [28]2 years ago

5 0

30 because 5x6= 30. All you have to do if the fractions are already simplified, is multiply the denominators together.

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A city police force is made up of 24% females. If there are 72 females on the force, how many males are on the force?

erastovalidia [21]

Answer:

228 males

Step-by-step explanation:

Let x be the number of males.

This means x + 72 is the total number of people.

So $\frac{72}{x+72}$ is the fraction of females in the force.

Thus, we can form the equation:

$\frac{72}{x+72} = 0.24$

$x+72 = \frac{72}{0.24}$

$x = \frac{72}{0.24} -72$

$x = 228$

Thus, the answer is 228 males.

6 0

3 years ago

What is the cordinate of point P?

Rom4ik [11]

Is there a graph so we can see where point p is located?

4 0

3 years ago

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To create an image, Figure D is going to be reflected across the y-axis, rotated 180° around the point indicated in the figure,

uranmaximum [27]

The image and pre-image are congruent

8 0

3 years ago

Select the equivalent expression. 2^-4= <br> Choose 1 answer<br> a)1/2^4<br> b)-2^4<br> c)(-2)^4

Marrrta [24]

Answer: A 1/2 ^4

Step-by-step explanation:

3 0

1 year ago

Read 2 more answers

A student committee is to consist of 2 freshmen, 5 sophomores, 4 juniors, and 3 seniors. If 6 freshmen, 13 sophomores, 8 juniors

mezya [45]

<h3>Answer: 491,891,400</h3>

Delete the commas if necessary.

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Explanation:

There are 6 freshmen total and we want to pick 2 of them, where order doesn't matter. The reason it doesn't matter is because each seat on the committee is the same. No member outranks any other. If the positions were labeled "president", "vice president", "secretary", etc, then the order would matter.

Plug n = 6 and r = 2 into the nCr combination formula below

$n C r = \frac{n!}{r!(n-r)!}\\\\6 C 2 = \frac{6!}{2!*(6-2)!}\\\\6 C 2 = \frac{6!}{2!*4!}\\\\6 C 2 = \frac{6*5*4!}{2!*4!}\\\\ 6 C 2 = \frac{6*5}{2!}\\\\ 6 C 2 = \frac{6*5}{2*1}\\\\ 6 C 2 = \frac{30}{2}\\\\ 6 C 2 = 15\\\\$

This tells us there are 15 ways to pick the 2 freshmen from a pool of 6 total.

Repeat those steps for the other grade levels.

n = 13 sophomores, r = 5 selections leads to nCr = 13C5 = 1287. This is the number of ways to pick the sophomores.

You would follow the same type of steps shown above to get 1287. Let me know if you need to see these steps.

Similarly, 8C4 = 70 is the number of ways to pick the juniors.

Lastly, 14C3 = 364 is the number of ways to pick the seniors.

-----------------------------

To recap, we have...

15 ways to pick the freshmen
1287 ways to pick the sophomores
70 ways to pick the juniors
364 ways to pick the seniors

Multiply out those values to get to the final answer.

15*1287*70*364 = 491,891,400

This massive number is a little under 492 million.

7 0

2 years ago