1/5 and 5/6 what number could be a common denominator for these two fractions:

Mathematics

1 answer:

Likurg_2 [28]2 years ago

5 0

30 because 5x6= 30. All you have to do if the fractions are already simplified, is multiply the denominators together.

You might be interested in

A chain has a ribbon tied to it every 2/3 foot. If the chain is 10 2/3 feet long, how many ribbons are tied to the chain??

patriot [66]

Answer:

16 ribbons

Step-by-step explanation:

Given the length of the chain as 10 $\frac{2}{3}$ and there is a ribbon tied to it every $\frac{2}{3}$ , we can take the total length of the chain and divide by the measure of $\frac{2}{3}$ :

$10\frac{2}{3}=\frac{32}{3}$

$\frac{\frac{32}{3}}{\frac{2}{3}}=\frac{32}{3}*\frac{3}{2}=\frac{96}{6}=16$

When dividing with fractions, we use the rule of 'keep/change/flip' to keep the first fractions, change the operation to multiplication and flip the second fraction.

7 0

3 years ago

Please solve equations by completing square

BlackZzzverrR [31]

$x^2-4x+1=0\\
x^2-4x+4-3=0\\
(x-2)^2=3\\
|x-2|=\sqrt3\\
x-2=\sqrt3 \vee x-2=-\sqrt3\\
x=2+\sqrt3 \vee x=2-\sqrt3$

$x^2+6x-9=0\\
x^2+6x+9-18=0\\
(x+3)^2=18\\
|x+3|=\sqrt{18}=3\sqrt2\\
x+3=3\sqrt2 \vee x+3=-3\sqrt2\\
x=-3+3\sqrt2 \vee x=-3-3\sqrt2\\$

$x^2+20x+3=0\\
x^2+20x+100-97=0\\
(x+10)^2=97\\
|x+10|=\sqrt{97}\\
x+10=\sqrt{97} \vee x+10=-\sqrt{97}\\
x=-10+\sqrt{97} \vee x=-10-\sqrt{97}$

$x^2-2x-5=0\\
x^2-2x+1-6=0\\
(x-1)^2=6\\
|x-1|=\sqrt6\\
x-1=\sqrt6 \vee x-1=-\sqrt6\\
x=1+\sqrt6 \vee x=1-\sqrt6$

8 0

4 years ago

AREA UNDER A CURVE<br><br><br> please explain too ty <3

Delicious77 [7]

I don’t even know lol I struggled with this too,

4 0

2 years ago

6) The height of any child in Mr. Diaz's kindergarten class is no greater than 46 inches.

kakasveta [241]

Answer:

full arrow going left from 46

Step-by-step explanation:

6 0

3 years ago

Solve the inequality 4(x+3) less than of equal to 41

Lelu [443]

Answer:

x= 1,2,3,4,5,6,7,8,9,10 so simpal

6 0

3 years ago