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2 years ago

Which is greater 3yd or 30ft

Mathematics

1 answer:

Volgvan2 years ago

8 0

Answer: 30 feet is greater

Step-by-step explanation:

3 yards is 9 feet (1 yard is 3 feet). 9 < 30. 30 feet is more than 9 feet, and 9 feet is equal to 3 yards so 30 feet is greater than 3 yards

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Which of the following illustrates the truth value of the following mathematical statements? 6 + 3 = 9, and 5 • 5 = 20

aleksley [76]

You answer should be
C. T F → F

6 0

3 years ago

Select the correct comparison.

Delicious77 [7]

The true comparison is the typical value is greater in set A. The spread is greater in set B.

<h3>What is the true comparison?</h3>

Spread is used to measure the variability of a data set. Range can be used to measure spread. Range is the difference between the largest number and the smallest number in the dataset.

Spread of set A = 7 - 5 = 2
Spread of set B = 8 - 1 = 7

The median can be used to measure the typical value of the dataset. Median is the number at the center of the data set.

Median of set A = 6
Median of set B = 4

To learn more about median, please check: brainly.com/question/14746682

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8 0

2 years ago

What is the result of a dilation of scale factor 3 centered at the origin of the line 2y + 3x=10?? PLEASE HELP PLEASEEEEEEEEE

maks197457 [2]

Given:

The equation of a line is:

$2y+3x=10$

The line is dilated by factor 3.

To find:

The result of dilation.

Solution:

The equation of a line is:

$2y+3x=10$

For $x=0$ ,

$2y+3(0)=10$

$2y+0=10$

$y=\dfrac{10}{2}$

$y=5$

For $x=2$ ,

$2y+3(2)=10$

$2y+6=10$

$2y=10-6$

$2y=4$

Divide both sides by 2.

$y=\dfrac{4}{2}$

$y=2$

The given line passes through the two points A(0,5) and B(2,2).

If the line dilated by factor 3 with origin as center of dilation, then

$(x,y)\to (3x,3y)$

Using this rule, we get

$A(0,5)\to A'(3(0),3(5))$

$A(0,5)\to A'(0,15)$

Similarly,

$B(2,2)\to B'(3(2),3(2))$

$B(2,2)\to B'(6,6)$

The dilated line passes through the points A'(0,15) and B'(6,6). So, the equation of dilated line is:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-15=\dfrac{6-15}{6-0}(x-0)$

$y-15=\dfrac{-9}{6}(x)$

$y-15=\dfrac{-3}{2}x$

Multiply both sides by 2.

$2(y-15)=-3x$

$2y-30=-3x$

$2y+3x=30$

Therefore, the equation of the line after the dilation is $2y+3x=30$ .

3 0

2 years ago

. A special safe lets you choose from 9 symbols for a 3-symbol-long pass code. You may enter a symbol any number of times. How m

Lady_Fox [76]

The question is an illustration of combination and there are 729 potential pass codes available

<h3>How to determine the number of potential pass codes?</h3>

The given parameters are

Symbols available = 9

Length of pass code = 3

From the question, we understand that a symbol may be entered any number of times.

This means that each of the 9 available symbols can be used three times

So, the number of potential pass codes is

Passcodes = 9 * 9 * 9

Evaluate the product

Passcodes = 729

Hence, there are 729 potential pass codes available