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FrozenT [24]
3 years ago
10

Please help.. Answer number 34 and 35. For number 34 find the measures of the numbered angles in each isosceles trapezoid. For n

umber 35 find the measures of the numbered angles in each kite.

Mathematics
1 answer:
Alexxx [7]3 years ago
5 0

Answer:

33. m∠1 = 135°, ∠3 = 45°, ∠2 = 135°

34. m∠1 = 80°, m∠2 = 100°, m∠3 = 100°

35. m∠1 = 90°, m∠2 = 25°

Step-by-step explanation:

33. The given parameters of the isosceles trapezoid are;

The measure of one of the base angles = 45°

For an isosceles trapezoid, the base angles are equal, therefore, we have;

The measure of the other base angle = m∠3 = 45°

Similarly, m∠1 = m∠2

Also, we have;

The sum of the interior angles in a trapezoid = The sum of the interior angles in a quadrilateral = 360°

∴ 45° + m∠3 + m∠1 + m∠2 = 360°

By substituting the known values, we have;

45° + 45° + m∠1 + m∠2 = 360°

From m∠1 = m∠2, we have;

45° + 45° + m∠1 + m∠1 = 90° + 2·m∠1 = 360°

2·m∠1 = 360° - 90° = 270°

∴ m∠1 = 270°/2 = 135°

m∠1 = 135° = m∠2

Therefore, we have;

∠3 = 45°, ∠1 = 135°, ∠2 = 135°

34. The measure of the base angles = 80°

∴ The measure of the other base angle = m∠1 = 80°

m∠2 = m∠3

80° + m∠1 + m∠2 + m∠3 = 360°

∴ 80° + 80° + 2·m∠2 = 360°

m∠2 = (360° - (80° + 80°))/2 = 100°

m∠2 = 100° = m∠3

35. The kite comprises of two half isosceles triangles

The base angles of the right half isosceles triangle = 65°

The angle formed by the diagonals of the kite = 90° (Perpendicular diagonals theorem)

Therefore, m∠1 = 90°

The diagonals bisect the angles at the vertices (Kite theorem)

Therefore, we have;

65° + 90° + m∠2 = 180°

m∠2 = 180° - (65° + 90°) = 25°

m∠2 = 25°.

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