Answer:
The probability that a randomly selected call time will be less than 30 seconds is 0.7443.
Step-by-step explanation:
We are given that the caller times at a customer service center has an exponential distribution with an average of 22 seconds.
Let X = caller times at a customer service center
The probability distribution (pdf) of the exponential distribution is given by;

Here,
= exponential parameter
Now, the mean of the exponential distribution is given by;
Mean =
So,
⇒
SO, X ~ Exp(
)
To find the given probability we will use cumulative distribution function (cdf) of the exponential distribution, i.e;
; x > 0
Now, the probability that a randomly selected call time will be less than 30 seconds is given by = P(X < 30 seconds)
P(X < 30) =
= 1 - 0.2557
= 0.7443
Answer:
x/3 ≤ 5
I'm not sure if this is what you were looking for. If not, please be more specific in your questions!
Answer: x=7
Step-by-step explanation:
Since AB is a bisector, it cuts the angle in half, and since we know that the angle is a right angle, we know it’s 90 degrees, so knowing that you use the equation 7x-4= 45 (since 45 is half of 90), add 4 to both sides so you have 7x=49, the divide 49 by 7 and you get 7, so x= 7