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irinina [24]
3 years ago
6

Use the diagram to answer the questions

Mathematics
1 answer:
IRISSAK [1]3 years ago
8 0

Answer:

1.  B. BD

2. C. 15

3. A. 2

Step-by-step explanation:

1.  From the figure,

∠DAB = ∠DAC

Therefore, BD is the bisector of ∠ABC.


2.  From the figure, IG = GH

3x = 5x - 10

10 = 5x - 3x

2x = 10

x = 5

So, GH = 5x - 10

= 5(5) - 10

= 25 - 10

= 15

Therefore, GH = 15.


3.  From the figure,

∠DAB = ∠DAC

10y = 8y + 4

10y - 8y = 4

2y = 4

y = 2

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Select the correct product.<br><br> (y + z)3
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Answer:

3y + 3z

Step-by-step explanation:

(y + z)3

As the parenthesis contains 2 different variables, we cannot add them

Distribute (Multiply 3 by y and z)

3y + 3z

This is the simplest that this expression can get

Hope this helps :)

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The complement of 4 heads in the toss of 4 coins is
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Answer:

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In a study of the relationship between pet ownership and physical activity in older adults, 586 subjects reported that they owne
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Answer:

Step-by-step explanation:

In a study of the relationship between pet ownership and physical activity in older adults, 586 subjects reported that they owned a pet, while 1931 reported that they did not. Give a 98% confidence interval for the proportion of older adults in this population who are pet owners. Lower limit Incorrect: Your answer is incorrect. Upper limit

p ± z × (1 - p/n)

z = 98%

p = 586/1931

= 0.3034697048

n = 1931

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Confidence interval =

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3 years ago
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2 years ago
In 2008, the average household debt service ratio for homeowners was 13.2. The household debt service ratio is the ratio of debt
ankoles [38]

Answer:

t=\frac{13.88-13.2}{\frac{3.14}{\sqrt{44}}}=1.436    

df=n-1=44-1=43  

p_v =P(t_{(43)}>1.436)=0.079  

We see that the p value i higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly higher than 13.2 *the value of 2008 ).

Step-by-step explanation:

Information given

\bar X=13.88 represent the sample mean

s=3.14 represent the sample standard deviation

n=44 sample size  

\mu_o =13.2 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic (variable of interest)  

p_v represent the p value for the test

Hypothesis to test

We want to conduct a hypothesis in order to check if the true mean has increased from 2008 , and the system of hypothesi are:  

Null hypothesis:\mu \leq 13.2  

Alternative hypothesis:\mu > 13.2  

The statistic for this case is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Calculating the statistic

Replacing the info given we got:

t=\frac{13.88-13.2}{\frac{3.14}{\sqrt{44}}}=1.436    

P-value

The degrees of freedom are:

df=n-1=44-1=43  

Since is a right tailed test the p value is:  

p_v =P(t_{(43)}>1.436)=0.079  

Decision

We see that the p value i higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly higher than 13.2 *the value of 2008 ).

8 0
4 years ago
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