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Alona [7]
2 years ago
7

Fill in the blanks below.

Mathematics
1 answer:
mariarad [96]2 years ago
4 0

Answer: A: the answer is -7

B: the answer is $95.00

Step-by-step explanation: Pls mark me as Brainiest

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The distance between the point (2,1,1) and the plane x-2y=5 is​
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The given plane has normal vector

x-2y=5\implies\mathbf n=\langle1,-2,0\rangle

Scaling <em>n</em> by a real number <em>t</em> gives a set of vectors that span an entire line through the origin. Translating this line by adding the vector <2, 1, 1> makes it so that this line passes through the point (2, 1, 1). So this line has equation

\mathbf r(t)=\langle1,-2,0\rangle t+\langle2,1,1\rangle=\langle 2+t, 1-2t, 1\rangle

This line passes through (2, 1, 1) when <em>t</em> = 0, and the line intersects with the plane when

x-2y=5\implies(2+t)-2(1-2t)=5\implies5t=5\implies t=1

which corresponds the point (3, -1, 1) (simply plug <em>t</em> = 1 into the coordinates of \mathbf r(t)).

So the distance between the plane and the point is the distance between the points (2, 1, 1) and (3, -1, 1):

\sqrt{(2-3)^2+(1-(-1))^2+(1-1)^2}=\boxed{\sqrt5}

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2045064

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