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2 years ago

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What is the slope of the line that passes through the points (-5, 6)(−5,6) and (-9, -6)(−9,−6)? Write your answer in simplest fo

rm.

1 answer:

SVETLANKA909090 [29]2 years ago

3 0

Answer:

The final answer is 0

m = 0

You might be interested in

Y^2 + 18y - 41 = 0<br> Y= <br> Y=

lana66690 [7]

Answer:

y= -9+√122, or -9 - √122

Step-by-step explanation:

You have to solve the equation for y to find each variable of the quadratic and applying the quadratic formula.

after solved, I got the answer as decimal,

y = 2.0453610.....

i simpler form : y = 2.05

Also, an answer can be y= -9+√122, or -9 - √122

6 0

2 years ago

Bob spends 30 hours in 4 weeks of gardening. How many hours does he garden in 5 weeks

Mademuasel [1]

Answer:

37.5 hrs

Step-by-step explanation:

You do cross multiplication hours on top and weeks on the bottom.

4 0

3 years ago

Kyle is pulled back on a swing so that the rope forms an angle of 30° with the vertical. The distance from the top of the swing

olga_2 [115]

This would be 12 - 12*cos(30) = 12 - 6 $\sqrt{3}$ = 1.608 ft off the ground.

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=x%20%5Ctimes%20%20%5Cfrac%7B2%7D%7B3%7D%20%20%3D%201%20%5Ctimes%20%5Cfrac%7B1%7D%7B3%7D%20" id

Ulleksa [173]

The answer : x= one half

6 0

2 years ago

Given the functionf ( x ) = x^2 + 7 x + 10/ x^2 + 9 x + 20

vladimir1956 [14]

<em>x = -4 is a vertical asymptote for the function.</em>

<h2>Explanation:</h2>

The graph of $y=f(x)$ is a vertical has an asymptote at $x=a$ if at least one of the following statements is true:

$1) \ \underset{x\rightarrow a^{-}}{lim}f(x)=\infty\\ \\ 2) \ \underset{x\rightarrow a^{-}}{lim}f(x)=-\infty \\ \\ 3) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty \\ \\ 4) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty$

The function is:

$f(x)=\frac{x^2+7x+10}{x^2+9x+20}$

First of all, let't factor out:

$f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20} \\ \\ f(x)=\frac{x(x+5)+2(x+5)}{x(x+5)+4(x+5)} \\ \\ f(x)=\frac{(x+5)(x+2)}{(x+5)(x+4)} \\ \\ f(x)=\frac{(x+2)}{(x+4)}, \ x\neq 5$

From here:

$\bullet \ When \ x \ approaches \ -4 \ on \ the \ right: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(-4^{+}+2)}{(-4^{+}+4)} \\ \\ \\ The \ numerator \ is \ negative \ and \ the \ denominator \\ is \ a \ small \ positive \ number. \ So: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=-\infty$

$\bullet \ When \ x \ approaches \ -4 \ on \ the \ left: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(-4^{-}+2)}{(-4^{-}+4)} \\ \\ \\ The \ numerator \ is \ a \ negative \ and \ the \ denominator \\ is \ a \ small \ negative \ number \ too. \ So: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=+\infty$

Accordingly:

$x=-4 \ is \ a \ vertical \ asymptote \ for \\ \\ f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20}$

<h2>Learn more:</h2>

Vertical and horizontal asymptotes: brainly.com/question/10254973

#LearnWithBrainly

5 0

3 years ago