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2 years ago

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What is the slope of the line that passes through the points (-5, 6)(−5,6) and (-9, -6)(−9,−6)? Write your answer in simplest fo

rm.

1 answer:

SVETLANKA909090 [29]2 years ago

3 0

Answer:

The final answer is 0

m = 0

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The sum of two consecutive numbers is 35. What is the smallest number?

sweet-ann [11.9K]

Answer i got is 17, 18

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3 years ago

Sid brought $200 to the amusement park . the cost of admission is $16.25 , and the cost of a lunch is $6.50 . After Sid purchase

ra1l [238]

Let x represent the # of people in sid’s group: 200 - (16.25x + 6.50x) = 18.25
200 - 22.75x = 18.25
-22.75x = -181.75
x = about 8

if Sid is not included in the group, i think the answer is D. 7, but im not sure

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3 years ago

Find the discriminant and the number of real roots for this equation. x^2 + 2x + 8 = 0

ehidna [41]

Step-by-step explanation:

A is correct option there are no real roots

because discriminant is less than zero

5 0

3 years ago

A certain kind of sheet metal has, on average, 3 defects per 18 square feet. Assuming a Poisson distribution, find the probabili

Fofino [41]

Answer:

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

In this problem, we have that:

3 defects per 18 square feet.

So for 31 square feet, we have to solve a rule of three

3 defects - 18 square feet

x defects - 31 square feet

$18x = 3*31$

$x = \frac{31*3}{18}$

$x = 5.17$

So $\mu = 5.17$

Assuming a Poisson distribution, find the probability that a 31 square foot metal sheet has at least 4 defects.

Either it has three or less defects, or it has at least 4 defects. The sum of the probabilities of these events is decimal 1.

So

$P(X \leq 3) + P(X \geq 4) = 1$

We want $P(X \geq 4)$

So

$P(X \geq 4) = 1 - P(X \leq 3)$

In which

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.17}*(5.17)^{0}}{(0)!} = 0.0057$

$P(X = 1) = \frac{e^{-5.17}*(5.17)^{1}}{(1)!} = 0.0294$

$P(X = 2) = \frac{e^{-5.17}*(5.17)^{2}}{(2)!} = 0.0760$

$P(X = 3) = \frac{e^{-5.17}*(5.17)^{3}}{(3)!} = 0.1309$

So

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0057 + 0.0294 + 0.0760 + 0.1309 = 0.242$

Finally

$P(X \geq 4) = 1 - P(X \leq 3) = 1 - 0.242 = 0.758$

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

8 0

4 years ago

Please helppp ASAP Content attribution

Aliun [14]

Answer:

The LCD of the two given fraction is (x + 4)(x + 5)(x + 7)

Step-by-step explanation:

<em>In the algebraic fractions, the LCD is the least common denominator to find it do that:</em>

Factorize each denominator

Take all the factors without repeating factors

<em>Let us do that with our question</em>

∵ The denominator of the first fraction is m² + 9m + 20

→ Factorize it into two factors

∵ 20 = 4 × 5 ⇒ the last term

∵ 4 + 5 = 9 ⇒ the coefficient of the middle term

∴ m² + 9m + 20 = (x + 4)(x = 5)

∴ The factors of m² + 9m + 20 are (x + 4) and (x + 5)

<em>Do the same with the 2nd denominator</em>

∵ The denominator of the second fraction is m² + 11m + 28

→ Factorize it into two factors

∵ 28 = 4 × 7 ⇒ the last term

∵ 4 + 7 = 11 ⇒ the coefficient of the middle term

∴ m² + 11m + 28 = (x + 4)(x + 7)

∴ The factors of m² + 11m + 28 are (x + 4) and (x + 7)

∵ The factors of the two denominators are (x + 4), (x + 5), (x + 4), (x + 7)

→ LCD will be all factors without repeating which means we will

take the factor (x + 4) just one time, we will not repeat it.

∴ LCD = (x + 4)(x + 5)(x + 7)

∴ The LCD of the two given fraction is (x + 4)(x + 5)(x + 7)

5 0

3 years ago