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Tom [10]
3 years ago
5

Factor and solve. 12p^2-25p+12=0

Mathematics
2 answers:
Leokris [45]3 years ago
8 0

Answer:

{p}  =  \frac{4}{3}, \:   \frac{3}{4}

Step-by-step explanation:

12 {p}^{2}  - 25p + 12 = 0 \\  \\ \implies 12 {p}^{2}  - 16p - 9p + 12 = 0 \\  \\ \implies 4p(3 {p} - 4) -3( 3p  -  4)= 0 \\  \\ \implies (3 {p} - 4)( 4p  -  3)= 0 \\  \\ \implies (3 {p} - 4) = 0 \:  \: or \:  \: ( 4p  -  3)= 0 \\  \\ \implies 3 {p}  = 4\:  \: or \:  \: 4p   =  3 \\  \\  \implies  {p}  =  \frac{4}{3} \:  \: or \:  \: p   =   \frac{3}{4} \\  \\ \implies  {p}  =  \frac{4}{3}, \:   \frac{3}{4} \\  \\

Anvisha [2.4K]3 years ago
5 0
((22•3p2) + 25p) + 12

12 • 12 = 144

-9 + -16 = -25

12p2 - 16p - 9p - 12

4p • (3p-4)

3 • (3p-4)

(4p-3) • (3p-4)

Answer: (3p - 4) • (4p - 3)
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Answer:

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Step-by-step explanation:

To add two matrices you just need to add the corresponding entries together. In this case, we have that:

\left[\begin{array}{ccc}4&19&-5\\7&0&-14\end{array}\right] + \left[\begin{array}{ccc}-8&7&0\\-1&17&6\end{array}\right]=\left[\begin{array}{ccc}4-8&19+7&-5 + 0\\7-1&0+17&-14+6\end{array}\right] = \left[\begin{array}{ccc}-4&26&-5\\6&17&-8\end{array}\right]

Then, we conclude that the sume of the two matrices is:

\left[\begin{array}{ccc}4&19&-5\\7&0&-14\end{array}\right] + \left[\begin{array}{ccc}-8&7&0\\-1&17&6\end{array}\right] = \left[\begin{array}{ccc}-4&26&-5\\6&17&-8\end{array}\right]

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3 years ago
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