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Arisa [49]
2 years ago
6

In 2019, Company A purchased a commercial building with 8 retail units for $4,200,000. In 2021, Company A decided to sell this b

uilding for $4,500,000. Interpret the change as a percentage. Round to the nearest hundredth.
Mathematics
1 answer:
Otrada [13]2 years ago
5 0

The change as a percentage is 6.7 %

<h3>How to calculate the percentage change ?</h3>

The price of the building in the year 2021 is $4,200,00

The price of the building in 2021 is $4,500,000

Therefore the percentage change can be calculated as follows

= 4,500,000 - 4,200,000/4,500,000 × 100

= 300,000/4,500,000 × 100

= 0.066 × 100

= 6.7 %

Hence the percentage change is 6.7%

Read more here

brainly.com/question/16346390?referrer=searchResults

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You are standing 60 feet from the base of a 20-foot tall flagpole. What is 1
Rasek [7]

Answer: The angle of elevation is 18.4 degrees (Approximately)

Step-by-step explanation: Please refer to the picture attached for more details.

The pole from top to  bottom is 20 feet tall and is depicted as line FB. An observer is standing at a distance of 20 feet from the base of the pole, and that is depicted as line BA. The observer who is at point A looks up to the top of the flagpole at an angle of elevation shown as angle A.

Using angle A as the reference angle, line FB which is 20 feet would be the opposite (facing the reference angle), while line BA which is 60 feet would be the adjacent (that lies between the right angle and the reference angle).

Therefore, to calculate angle A;

Tan A = Opposite/Adjacent

Tan A = 20/60

Tan A = 1/3

Tan A = 0.3333

Checking with your calculator or table of values,

A = 18.4349°

Rounded to the nearest tenth,

A ≈ 18.4°

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3 years ago
Pls can any of you help with this.​
Lorico [155]
X=6 and Y= 6 square root 2
3 0
3 years ago
CAN SOMEONE PLEASE HELP ME ASAP PLEASEEEE!!!​
Rom4ik [11]

Answer:

11.4

Step-by-step explanation:

So we know that Triangle ACB is similar to Triangle EFD.

This means that their sides are proportional to each other.

We want to find x or side AB. To do so, we can set up a proportion.

The proportional side to AB is ED. Let's also use BC since we know its value. The proportional side to BC is DF. Thus:

\frac{AB}{ED}=\frac{BC}{DF}

Substitute x for AB, 3.8 for Ed, 15 for BC, and 5 for DF. Thus:

\frac{x}{3.8}=\frac{15}{5}

Reduce the right:

\frac{x}{3.8}=\frac{3}{1}

Cross multiply:

x=11.4

So, the value of x is 11.4

And we're done!

7 0
3 years ago
How to solve the problem
777dan777 [17]
Hope this helps.....

4 0
3 years ago
For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f
butalik [34]

\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k

Let

\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k

The curl is

\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)

where \partial_\xi denotes the partial derivative operator with respect to \xi. Recall that

\vec\imath\times\vec\jmath=\vec k

\vec\jmath\times\vec k=\vec i

\vec k\times\vec\imath=\vec\jmath

and that for any two vectors \vec a and \vec b, \vec a\times\vec b=-\vec b\times\vec a, and \vec a\times\vec a=\vec0.

The cross product reduces to

\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

\nabla\times\vec f=\vec0

which means \vec f is indeed conservative and we can find f.

Integrate both sides of

\dfrac{\partial f}{\partial y}=2xze^{2xyz}

with respect to y and

\implies f(x,y,z)=e^{2xyz}+g(x,z)

Differentiate both sides with respect to x and

\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}

2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}

4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}

\implies g(x,z)=4\sin(xz^2)+h(z)

Now

f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)

and differentiating with respect to z gives

\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}

2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}

\dfrac{\mathrm dh}{\mathrm dz}=0

\implies h(z)=C

for some constant C. So

f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C

3 0
4 years ago
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