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2 years ago

Find the slope of the line that passes through (1, -4) and (2, 6).

Mathematics

2 answers:

Charra [1.4K]2 years ago

7 0

The slope of this line is 10

Sholpan [36]2 years ago

7 0

Answer:

$\boxed{\sf{10}}$

Step-by-step explanation:

Use the slope formula.

Slope:

$\sf{\dfrac{y_2-y_1}{x_2-x_1}}}=\dfrac{rise}{run}$

y2=6

y1=(-4)

x2=2

x1=4

Solve.

$\sf{\dfrac{6-\left(-4\right)}{2-1}}=\dfrac{6+4=10}{2-1=1}=\dfrac{10}{1}=\boxed{\sf{10}}$

Therefore, the slope is 10, which is our answer.

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How much cardboard is needed to make the tissue box above? Square inches 8 3 3

Katen [24]

The amount of cardboard needed to make a cuboid box of dimensions 8 inch, 3 inches and 3 inches is 114 sq. inches.

<h3>What is the surface area of cuboid?</h3>

Let the three dimensions(height, length, width) be x, y,z units respectively.

The surface area of the cuboid is given by

$S = 2(a\times b + b\times c + c\times a)$

For this case, tissue box is almost cuboid shaped.

Also, its dimensions are given being 8 inches, 3 inches and 3 inches.

Suppose we measure the amount of cardboard needed in terms of area, then, the amount of cardboard needed to make that box(without any whole, full cuboid) is equal to the area of its surface(either outer or inner if we assume 0 inches thickness of cardboard),

Thus, we get:

Amount of cardboard needed = surface area of cuboid box with dimensions 8 by 3 by 3 (in inches)

= $2(8 \times 3 + 3 \times 3 + 3 \times 8) = 114 \: \rm in^2$

Thus, the amount of cardboard needed to make a cuboid box of dimensions 8 inch, 3 inches and 3 inches is 114 sq. inches.

Learn more about surface area of cuboid here:

brainly.com/question/13522634

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5 0

2 years ago

O 12 units<br> O 15 units<br> O 20 units<br> O 25 units

nadezda [96]

Answer:

12 units

Step-by-step explanation:

Because the two triangles are similar:

$\dfrac{x}{9}=\dfrac{16}{x} \\\\\\\dfrac{x^2}{9}=16 \\\\\\x^2=144 \\\\\\x=12$

Hope this helps!

3 0

3 years ago

Write an equation for the nth term of the arithmetic sequence −15, −33, −51, −69, .... An equation for the nth term of the

stira [4]

Given:

The arithmetic sequence is −15, −33, −51, −69.

To find:

The nth term of the arithmetic sequence.

Solution:

We have,

−15, −33, −51, −69

Here,

First term: a = -15

Common difference is

$d = -33-(-15)$

$d = -33+15$

$d = -18$

Now, nth term of an arithmetic sequence is

$a_n=a+(n-1)d$

Substitute a=-15 and d=-18.

$a_n=-15+(n-1)(-18)$

$a_n=-15-18n+18$

$a_n=-18n+3$

Therefore, the nth term of the given arithmetic sequence is $a_n=-18n+3$ .

4 0

3 years ago

Not drawn

Aleks04 [339]

We see that they are made up of identical squares, meaning that each side of each square is the same length. There are 12 square sides that make up the perimeter of A, so we can do 72/12 which is 6. We see there are ten total square lengths on the perimeter of b, so we can do 6 times 10 which is 60 cm. That’s your perimeter.

7 0

2 years ago

Which expression is the radical form of m to the power of -0.3333

Evgen [1.6K]

Answer:

A1/ ∛m

Step-by-step explanation:

m ^ (-1/3)

this is m to the cubed root in the denominator

1/ ∛m

8 0

3 years ago