Answer:
Step-Question: The amount of money spent weekly on cleaning, maintenance, and repairs at a large restaurant was ...
The amount of money spent weekly on cleaning, maintenance, and repairs at a large restaurant was observed over a long period of time to be approximately normally distributed, with mean ? = $615 and standard deviation ? = $38.
(a) If $646 is budgeted for next week, what is the probability that the actual costs will exceed the budgeted amount? (Round your answer to four decimal places.)
(b) How much should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will be exceeded in a given week is only0.08? (Round your answer to the nearest dollar.)
$by-step explanation:
The question in English
<span>Monica has 6 /10 kg of candy with which she fills 1/4 of a cellophane bag. What is the capacity of the bag?
</span>
we know that
6/10---------> 0.60
1/4----------> 0.25------> 25%
if 25% of a cellophane bag---------------> has a 0.60 kg of candy
100%-----------------------------------------> X
X=100*0.60/25--------> X=2.4 kg
the answer is
2.4 kg
the answer in Spanish
Sabemos que
6/10---------> 0.60
1/4----------> 0.25------> 25%
if 25% de la bolsa de celofan---------------> se llena con 0.60 kg de dulces
100% de la bolsa----------------------------------------->se llenara con X kg
X=100*0.60/25--------> X=2.4 kg
La respuesta es
2.4 kg
There is not enough detail for me to answer
Okay so the problem starts you off with the fraction (1/4). Sharing equally among 3 people would mean that you'd want to divide it by three so your equation would initially look like (1/4) / 3. Having two dividing signs is confusing so what you do is change the dividing into multiplying by the reciprocal of 3 = 1/3... This would make your expression (1/4) * (1/3) and when you simplify this you should get 1/12 as the answer.
60 is what percent of 200...
60/200 = x/100
200x = 6000
x = 6000/200
x = 30%...that means for every sale, the sales person gets a 30% commission
C(p) = 0.3p <==
