The answer is: 10 x¹³ y¹⁰ .
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1x^8 * 2y^(10) * 5x^5 =
1* 2* 5 * x^8 * x^5 * y^(10) =
10 * x^(8+5) * y^(10) =
10 * x^(13) * y^(10) = 10 x^(13) y^10 ; write as:
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10 x¹³ y¹<span>⁰ .
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Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r = 
= 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!
Answer: 207
Step-by-step explanation:
Let
x = 3a (first angle)
y = 3a (second angle)
z = 6a (third angle)
The total angle of a triangle is ALWAYS 180.
3a + 3a + 6a = 180
12a = 180
a = 15
Therefore, x = 45, y = 45, z = 90
Answer:
3.5
Step-by-step explanation:
First we use the concept of relative speed.
The rates of the 2 planes are 625 mph & 575 mph.
Relative speed will be:
(speed of plane A)+(speed of plane B)
=625+575
=1,200 mph
Distance=4200 miles
Thus the time taken for them to meet will be:
Time=distance/speed
=4200/1200
=3.5 hours
We therefore conclude that the planes met after 3.5 hours.
Hope this helps!
