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3 years ago

Determine the solution to the following set of linear equations by using the graph below

Mathematics

1 answer:

Olegator [25]3 years ago

4 0

Answer:

-49x=-3y=2

Step-by-step explanation:

3x+y=52x-2y=2

3x-52x=-2y-y=2

-49x=-3y=2

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Luis purchased a computer that was advertised as 2/5 off. The original price was $800. What is the amount that he paid?

juin [17]

Answer:

Step-by-step explanation:

<u>You divide $800 by 5 and get $160. Then multiply $160 by 2 and get $320. Then subtract $320 from $800 and get $480.</u>

3 0

3 years ago

Write a quadratic equation with the given roots. Write the equation in the form , where a, b, and c are integers. –7 and –2

larisa86 [58]

$\bf x= \begin{cases} -7\\ -2 \end{cases}\implies \begin{cases} x=-7\implies &x+7=0\\ x=-2\implies &x+2=0 \end{cases}\implies (x+7)(x+2)=\stackrel{y}{0} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\mathbb{FOIL}}{x^2+9x+14=y}~\hfill$

3 0

3 years ago

Read 2 more answers

-7=z/-6 solve for z pls help it 7th grade math and it’s on khan ;cc

trasher [3.6K]

Answer:

Step-by-step explanation:

I think it's 42 because 42/-6 is -7

6 0

4 years ago

Read 2 more answers

Help! PLZ, 20 PTS in 10 mins if possible thx !!!! A gym charges $55 for a monthly membership and an additional $4.50 for each yo

Rzqust [24]

Answer:

(70-55)/4.5=y rounded down to the nearest whole number

Step-by-step explanation:

The first step is to take away the $55 from $70

70-55=15

Simba has $15 to spend on the yoga classes, to find the number of yoga classes she can attend, you divide 15 by the amount a yoga class costs, $4.50

15/4.50=3 1/3

Because she can not have 1/3 of a yoga class, she can attend 3 yoga classes in her budget.

Hope this helps, if you have any questions feel free to ask

Have a good day! :)

8 0

4 years ago

In the diagram abc=adb=90, ad=p and dc=q. Use similar triangles to show that x2=pz<br> plzz anyoneee

kramer

Answer:

By comparing the ratios of sides in similar triangles ΔABC and ΔADB,we can say that $x^{2} =pz$

Step-by-step explanation:

Given that ∠ABC=∠ADC, AD=p and DC=q.

Let us take compare Δ ABC and Δ ADB in the attached file , ∠A is common in both triangles

and given ∠ABC=∠ADB=90°

Hence using AA postulate, ΔABC ≈ ΔADB.

Now we will equate respective side ratios in both triangles.

$\frac{AB}{AC}= \frac{AD}{AB}=\frac{BD}{BC}$

Since we don't know BD , BC let us take first equality and plugin the variables given in respective sides.

$\frac{x}{z}= \frac{p}{x}$

Cross multiply

$x^{2}=pz$

Hence proved.

7 0

4 years ago