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inn [45]
3 years ago
8

Car is driving at the rate of 58km per hour. How much time will it take to drive for distance of 32 miles? REASON?

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
7 0

As we are given

Car is driving at the rate of 58km per hour

First we will have to convert it into miles per hour

As we know that 1 km per hour =0.621371 miles per hour

So we can say 58km per hour=58*0.621371 miles per hour=36.0395 miles per hour

We are supposed to find -"How much time will it take to drive for distance of 32 miles"

As we know that

Distance=Speed*Time

Time=\frac{Distance}{Speed}\\ \\ Time= \frac{32 miles }{36.0395 mph}\\ \\ Time=0.8879 \ hr

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180 minus what = 45<br><br> i really need this answer thank you
LuckyWell [14K]

Answer: 135

Step-by-step explanation: All you need to do is 180-45=135.

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3 years ago
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Lana71 [14]
What's the question?
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3 years ago
Suppose the horses in a large stable have a mean weight of 975lbs, and a standard deviation of 52lbs. What is the probability th
Lubov Fominskaja [6]

Answer:

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 975, \sigma = 52, n = 31, s = \frac{52}{\sqrt{31}} = 9.34

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable?

pvalue of Z when X = 975 + 15 = 990 subtracted by the pvalue of Z when X = 975 - 15 = 960. So

X = 990

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{990 - 975}{9.34}

Z = 1.61

Z = 1.61 has a pvalue of 0.9463

X = 960

Z = \frac{X - \mu}{s}

Z = \frac{960 - 975}{9.34}

Z = -1.61

Z = -1.61 has a pvalue of 0.0537

0.9463 - 0.0537 = 0.8926

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

7 0
3 years ago
I need help with all of these I don’t get it
pochemuha
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The product of five rational numbers is positive. At most, of these rational numbers can be negative
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Answer: A. 1

Step-by-step explanation:

sorry if im wrong

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