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oee [108]
3 years ago
14

The larger of two numbers is 1 more than twice the

Mathematics
1 answer:
stellarik [79]3 years ago
7 0

Answer:

Step-by-step explanation:

Hi there!

Let the smaller number be x and the larger number be 2x+1.

According to the question,

The sum of the numbers is 20 less than three

times the larger.

i.e x + (2x+1)= 3*(2x+1) - 20

or, x + 2x +1 = 6x + 3 -20

or, 3x + 1 = 6x - 17

or, 3x = 18

or x= 18/3

x = 6

And 2x+1 = 2*6+1 = 13.

Therefore the smaller number is 6 and larger number is 13.

Hope it helps!

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Answer:

No Solution.

Step-by-step explanation:

-6(x-7)+6(x+5)=73

-6x+42+6x+30=73

72=73

no solution

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3 years ago
Do any of ya'll know the answer of this a=75.6==55?
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Find the value of x in the triangle shown
nevsk [136]

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the answer is A the square root of 80.

Step-by-step explanation:

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The number e is an irrational number approximately equal to 2.718 between which pair of square roots does e fall
Shkiper50 [21]

Answer:

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Step-by-step explanation:

Please kindly check the attached file for explanation.

3 0
3 years ago
Find the vector projection of B onto A if A = 5i + 11j – 2k,B = 4i + 7k​
valkas [14]

Answer:

\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\

Step-by-step explanation:

Given A = 5i + 11j – 2k and B = 4i + 7k​, the vector projection of B unto a is expressed as proj_ab = \dfrac{b.a}{||a||^2} * a

b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)

note that i.i = j.j = k.k  =1

b.a = 5(4)+11(0)-2(7)

b.a = 20-14

b.a = 6

||a|| = √5²+11²+(-2)²

||a|| = √25+121+4

||a|| = √130

square both sides

||a||² = (√130)

||a||²  = 130

proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\

<em>Hence the projection of b unto a is expressed as </em>\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\<em></em>

7 0
4 years ago
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