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Kipish [7]
3 years ago
7

Who walks at a faster rate: someone who walks 60 feet in 10 seconds or someone who takes 5 seconds to walk 25 feet?

Mathematics
1 answer:
harkovskaia [24]3 years ago
6 0

Well, I don't know.
Let's figure it out together.
The best way to do that is to compare their unit rates:

The first woman's unit rate is  (60 ft / 10 sec)

                                             = (60 / 10) (ft/sec) = 6 ft/sec .

The second woman's unit rate is  (25 ft / 5 sec)

                                                =   (25 / 5) (ft/sec) = 5 ft/sec .

Now we can see that the first woman walks 1 ft/sec faster
than the second one does.

You might be interested in
What is the value of x?<br><br> Please help! Thanks!
leonid [27]

Answer:

x=75

Step-by-step explanation:

We can use proportions to solve this problem.  Put the side of the small triangle over the side of the large triangle.

42           50

------ = ----------

42+63        50+x

42           50

------ = ----------

105          50+x

Using cross products

42(50+x) = 50*(105)

2100+42x = 5250

Subtract 2100 from each side

2100-2100+42x = 5250-2100

42x =3150

Divide by 42

42x/42 = 3150/42

x = 75


8 0
4 years ago
Solve for e.<br><br> 4/3=-6e-5/3
cricket20 [7]

Answer:

e = 1/2

Step-by-step explanation:

to solve foe e in  this 4/3=-6e-5/3

solution

4/3=-6e-5/3

4/3 + 5/3 = 6e

find the lcm of the left hand side

4 + 5/3 = 6e

9/3 = 6e

cross multiply

3 x 6e = 9 x 1

18e = 9

divide both sides by the coefficient of e which is 18

18e /18 = 9/18

e = 1/2

therefore the value of e in the expression above is evaluated to be equals to 1/2

5 0
4 years ago
A circle has a radius of 7.5 centimeters and a central angle AOB that measures 90 degrees. What is the length of the intercepted
Julli [10]
Since there are 360^{\circ} in a circle, and central \angle AOB = 90^{\circ}, you can see that the part "sliced out" by the central angle is \frac{90^{\circ}}{360^{\circ}} = \frac{1}{4} of the whole circle.

This means that the length of the intercepted arc \stackrel{\frown}{AB} is \frac{1}{4} of the circumference of the circle. So,

\stackrel{\frown}{AB} = \frac{1}{4}(2 \pi r) = \frac{1}{4}(2 \pi (7.5 cm)) = \bf \frac{15 \pi}{4} cm



6 0
3 years ago
What is 46,491 rounded to the nearest ten thousand
postnew [5]
50,000 is the nearest ten thousand.
8 0
3 years ago
Read 2 more answers
Here ya go heres those last questions :)
skelet666 [1.2K]
The 3 bubble is the correct answer.

being that you're looking for 3.60 in quarters(25) and nickles (5) which add up to be 3.60 so 25q+5n=360
4 0
4 years ago
Read 2 more answers
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