1. You have the following equations:
<span>
y=−2x+5 (i)
3x−4y=2 (ii)
2. You must substitute the equation (i) into the equation (ii), as below:
</span>3x−4y=2
3x-4(−2x+5)=2
3x+8x-20=2
11x-20=2
3. Now, you must clear the variable "x":
11x=2+20
x=22/11
x=2
4. You have the value of "x", so you can find the value of "y". When you substitute x=2 into the equation (i), you obtain:
y=−2x+5
y=-2(2)+5
y=-4+5
y=1
5. Therefore, the answer is:
x=2
y=1
Answer:
1/9 1/10 1/11 1/12 1/13 and so on
Step-by-step explanation:
Answer:
X = - 5/3 or X = -1.6
Step-by-step explanation:
Move variable to the left hand side and change its sign
Collect like terms
Divide both sides of the equation by -3
Two-Digit Divisor in Long Division. Two-Digit Divisor in Long Division. This is a complete lesson with examples and exercises about two-digit divisor in long division, meant for initial teaching in 5th grade.
7(3x-2)+4(x+5)
= 7*(3x)-7*2+4x+4*5 (distributive property)
= 21x -14 +4x +20
= 25x +6
Final answer: 25x+6.
Hope this helps~
