What is the solution to the system of equations? Use the substitution method. {y=−2x+5 {3x−4y=2 Enter your answer in the boxes.

1 answer:

7 0

1. You have the following equations:

y=−2x+5 (i)
3x−4y=2 (ii)

2. You must substitute the equation (i) into the equation (ii), as below:

3x−4y=2
3x-4(−2x+5)=2
3x+8x-20=2
11x-20=2

3. Now, you must clear the variable "x":

11x=2+20
x=22/11
x=2

4. You have the value of "x", so you can find the value of "y". When you substitute x=2 into the equation (i), you obtain:

y=−2x+5
y=-2(2)+5
y=-4+5
y=1

5. Therefore, the answer is:

x=2
y=1

You might be interested in

Suppose f(x) = 6x^2 + 2x − 7 and g(x) = 4x − 3. Find each of the following functions.

FinnZ [79.3K]

Step-by-step explanation:

(f+g)(x) ➡ f(x) + g(x) ➡ 6x^2 + 2x -7 + 4x - 3 =6x^2 + 6x - 10

(f-g)(x) ➡ f(x) - g(x) ➡ 6x^2 + 2x - 7 -4x + 3 = 6x^2 -2x -4

8 0

3 years ago

An Internet reaction time test asks subjects to click their mouse button as soon as a light flashes on the screen. The light is

Ganezh [65]

Answer:

(a) 0.20

(b) 31%

Step-by-step explanation:

The random variable Y models the amount of time the subject has to wait for the light to flash.

The density curve represents that of an Uniform distribution with parameters a = 1 and b = 5.

So, $Y\sim Unif(1,5)$

(a)

The area under the density curve is always 1.

The length is 5 units.

Compute the height as follows:

$\text{Area under the density curve}=\text{length}\times \text{height}$

$1=5\times\text{height}\\\\\text{height}=\frac{1}{5}\\\\\text{height}=0.20$

Thus, the height of the density curve is 0.20.

(b)

Compute the value of P (Y > 3.75) as follows:

$P(Y>3.75)=\int\limits^{5}_{3.75} {\frac{1}{b-a}} \, dy \\\\=\int\limits^{5}_{3.75} {\frac{1}{5-1}} \, dy\\\\=\frac{1}{4}\times [y]^{5}_{3.75}\\\\=\frac{5-3.75}{4}\\\\=0.3125\\\\\approx 0.31$