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3 years ago

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What is the solution to the system of equations? Use the substitution method. {y=−2x+5 {3x−4y=2 Enter your answer in the boxes.

1 answer:

Nataly_w [17]3 years ago

7 0

1. You have the following equations:
<span>
y=−2x+5 (i)
3x−4y=2 (ii)

2. You must substitute the equation (i) into the equation (ii), as below:

</span>3x−4y=2
3x-4(−2x+5)=2
3x+8x-20=2
11x-20=2

3. Now, you must clear the variable "x":

11x=2+20
x=22/11
x=2

4. You have the value of "x", so you can find the value of "y". When you substitute x=2 into the equation (i), you obtain:

y=−2x+5
y=-2(2)+5
y=-4+5
y=1

5. Therefore, the answer is:

x=2
y=1

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2 years ago

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Answer:

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Step-by-step explanation:

1) Use Division Distributive Property: (x/y)^a = x^a/y^a.

$\frac{1}{ {27}^{x - 8} } = 27$

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5) Use Definition of Common Logarithm: b^a = x if and only if log<u>b</u><u> </u>(x) = a.

$log_{27}1 = x - 7$

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7) Use rule of 1: log 1 = 0.

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9) Add 7 to both sides.

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10) Switch sides.

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<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>7</u><u>.</u>

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3 years ago

The midpoint of AB is M (0, -3). If the coordinates of AA are (2, 1) what are the coordinates of BB?

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Answer:

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Step-by-step explanation:

Midpoint is (0, -3)

A(x₁, y₁) B(x₂, y₂)

A(2, 1)

$Midpoint = (\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2} )\\\\Midpoint = (\frac{2+ x_{2} }{2}, \frac{1 + y_{2} }{2} )$

$(0, -3) = (\frac{2+ x_{2} }{2}, \frac{1 + y_{2} }{2} )$

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