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1 year ago

Answer ASAP if you dont know the answer do not answer be 100% sure. Please i need a better grade in math.

Mathematics

1 answer:

andrezito [222]1 year ago

4 0

Answer: Complementary Angles

Step-by-step explanation:

The angles shown add up to 90°. Complementary angles are angles that also add up to 90°

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Plss answer!! <br>MERRY Christmas!!! <br>Critical Question. AAAAA

liberstina [14]

Answer:

Step-by-step explanation:

abc = 1

We have to prove that,

$\frac{1}{1+a+b^{-1}}+\frac{1}{1+b+c^{-1}}+\frac{1}{1+c+a^{-1}}=1$

We take left hand side of the given equation and solve it,

$\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+\frac{1}{c}}+\frac{1}{1+c+\frac{1}{a}}$

Since, abc = 1,

$\frac{1}{c}=ab$ and c = $\frac{1}{ab}$

By substituting these values in the expression,

$\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+\frac{1}{c}}+\frac{1}{1+c+\frac{1}{a}}=\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+ab}+\frac{1}{1+\frac{1}{ab}+\frac{1}{a}}$

$=\frac{b}{b+ab+1}+\frac{1}{1+b+ab}+\frac{ab}{ab+1+b}$

$=\frac{1+b+ab}{1+b+ab}$

$=1$

Which equal to the right hand side of the equation.

Hence, $\frac{1}{1+a+b^{-1}}+\frac{1}{1+b+c^{-1}}+\frac{1}{1+c+a^{-1}}=1$

5 0

2 years ago

Why are (1,2) and(2,1) not equal ordered pair?

vladimir1956 [14]

Answer:

The pairs ( 1 , 2 ) and ( 2 , 1 ) are not equal because their respective elements are not equal.

Step-by-step explanation:

The pair of elements which are in specific order is called an ordered pair. The pair ( 1 , 2 ) is not same as the pair ( 2 , 1 ). In the pair ( 1 , 2 ) 1 is in the first position and 2 is in the second position. In the pair ( 2 , 1 ), 2 is in the first position and 1 is in the second position.

Two ordered pairs ( a , b ) and (c , d ) are said to be equal if a = c and b = d. We write ( a , b ) = ( c , d ).

Hope I helped!

Best regards!!

8 0

2 years ago

Please this a really easy question. Does this mean I got an A on this test?! Please answer!!!!!!!!!!!!!!!

AnnZ [28]

Answer:

yes it does. good job on your A.

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

POSSIBLE POINTS: 5.88

Bess [88]

The function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)

<h3>How to write a function of the length z in meters of the side parallel to the wall?</h3>

The given parameters are:

Perimeter = 210 meters

Let the length parallel to the wall be represented as z and the width be x

So, the perimeter of the fence is

P = 2x + z

This gives

210 = 2x + z

Make x the subject

x = 1/2(210 - z)

The area of the wall is calculated as

A = xz

So, we have

A = 1/2(210 - z) * z

This gives

A = z/2(210 - z)

Rewrite as

A(z) = z/2(210 - z)

Hence, the function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)