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Aleksandr-060686 [28]
3 years ago
6

A hairstylist schedules 1/4 hour tot trim a customer's hair and 1/6 hour to style the customer's hair. The hairstylist plans to

work 3 1/2 hours each day for 5 days each week. How many appointments can the hairstylist schedule each week if each customer must be trimmed and styled?
Mathematics
1 answer:
iragen [17]3 years ago
7 0

A hairstylist schedules 1/4 hour tot trim a customer's hair and 1/6 hour to style the customer's hair.

Hours scheduled for 1 customer = trim + style the customer hair

= \frac{1}{4} + \frac{1}{6}=\frac{10}{24} = \frac{5}{12}  

So 1 customer can be  scheduled for 5/12 hours

The hairstylist plans to work 3\frac{1}{2} or \frac{7}{2}hours each day

We find out how many customers can be scheduled per day

\frac{\frac{7}{2}}{\frac{5}{12}}=\frac{42}{5} = 8.4

Its approximately 8 appointments per day

He works for 5 days in a week

So 5 * 8 appointments = 40 appointments

40 appointments can the hairstylist schedule each week if each customer must be trimmed and styled



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we have the function

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Part a

For t=7

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\begin{gathered} E=\sin \frac{\pi}{14}14 \\ E=0 \end{gathered}

For t=21

\begin{gathered} E=\sin \frac{\pi}{14}21 \\ E=-1 \end{gathered}

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\begin{gathered} E=\sin \frac{\pi}{14}28 \\ E=0 \end{gathered}

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\begin{gathered} E=\sin \frac{\pi}{14}35 \\ E=1 \end{gathered}

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Remember that

The Period goes from one peak to the next

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1 year ago
A sequence of 1 million iid symbols(+1 and +2), Xi, are transmitted through a channel and summed to produce a new random variabl
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Answer:

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given data

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solution

sequence will be here as

P{Xi = k } = 0.4              for k = +1

                  0.6              for k = +2

and define is

x1  + x2 + ................ + X1000000

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E(w) = 1000000 ( 0.4 × 1 + 0.6 × 2)

E(w) = 1600000

and

for variance of W

v(w) = V ( x1  + x2 + ................ + X1000000 )    ..........................2

v(w) = V x1  + V x2 + ................  + V  X1000000

here also same as that xi are i.e d so cov(xi, xj ) = 0 and i ≠ j

so

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Answer:

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