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Aleksandr-060686 [28]
3 years ago
6

A hairstylist schedules 1/4 hour tot trim a customer's hair and 1/6 hour to style the customer's hair. The hairstylist plans to

work 3 1/2 hours each day for 5 days each week. How many appointments can the hairstylist schedule each week if each customer must be trimmed and styled?
Mathematics
1 answer:
iragen [17]3 years ago
7 0

A hairstylist schedules 1/4 hour tot trim a customer's hair and 1/6 hour to style the customer's hair.

Hours scheduled for 1 customer = trim + style the customer hair

= \frac{1}{4} + \frac{1}{6}=\frac{10}{24} = \frac{5}{12}  

So 1 customer can be  scheduled for 5/12 hours

The hairstylist plans to work 3\frac{1}{2} or \frac{7}{2}hours each day

We find out how many customers can be scheduled per day

\frac{\frac{7}{2}}{\frac{5}{12}}=\frac{42}{5} = 8.4

Its approximately 8 appointments per day

He works for 5 days in a week

So 5 * 8 appointments = 40 appointments

40 appointments can the hairstylist schedule each week if each customer must be trimmed and styled



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2 \ \frac{2}{3}

Step-by-step explanation:

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At the park there is a pool shaped like a circle. A ring-shaped path goes around the pool. Its inner diameter is 22yd and its ou
jeka94
First, we need to think about what we're actually solving for: the area of the path. To find this, we can find the area of the whole thing, minus the area of the pool.

The diagram would look something like the picture I attached. We know that to find the area of a circle, you do πr^2. The radius is half of the diameter, so halve the diameters:

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Then solve for the area of both circles.
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</span>
Next, subtract the area of the pool from the area of the whole thing to find the area of the walkway:
804.25 - 380.13 = 424.12 (area of the walkway)

Finally, divide the area of the walkway by 6 to see how many gallons of paint you'll need:

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4 years ago
Last month, Justina dog ate 50 cans of dog food in 30 days. How many cans should Justin buy for the next 6 days
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Answer:

The answer is 7 2/3 cans for the next 6 days.

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3 years ago
A school is planning to construct two rectangular play areas in the playground. The length of play area A must be 1 foot longer
Anna11 [10]

Answer:

А.The system has two solutions, but only one is viable because the other results in a negative width.

Step-by-step explanation:

Given

Let:

L_A \to length of play area A

W_A \to width of play area A

L_B \to length of play area B

W_B \to width of play area B

x \to Area of A

y \to Area of B

From the question, we have the following:

L_A = 1 + 4W_A

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The area of A is:

x = L_A * W_A

This gives:

x = (1 + 4W_A) * W_A

Open bracket

x = W_A + 4W_A^2

The area of B is:

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Substitute: W_B = 2 + W_A

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Open brackets

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Expand

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x = y

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W_A = -14.1 or W = 1.13 --- approximated

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W = 1.19

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