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3 years ago

5

Anyone for geometry #’s 5 & 6

1 answer:

vesna_86 [32]3 years ago

3 0

Answer:

5. m < 1 = 72 degrees.

6. m < 1 = 80 degrees.

Step-by-step explanation:

5. < 1 = 72 degrees.

If we draw a line through the point of < 1, We see that We have have 2 angles of 40 and 32 ( alternate angles).

6. By the same reasoning m < 1 = 60 + 20

= 80 degrees.

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PLS HURRY WILL GIVE BRAINLIEST

marta [7]

Answer:

C. y= 6x-5

Step-by-step explanation:

Given Information :

Slope (m) = 6

y-intercept (b) = -5

Equation of a line :

y=mx+b

Where :

m = slope

b = y-intercept

So , with the given the information , the equation is :

$y = 6x - 5$

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3 years ago

The line plot above shows the distance in miles Luna runs each day. What is the difference in distance between the fewest miles

alukav5142 [94]

Answer:

The answer is 4

Step-by-step explanation:

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2 years ago

What is the simplified form of the following expression?

USPshnik [31]

Option C:

$$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}$

Solution:

Given expression is

$$\sqrt[3]{\frac{4 x}{5}}$

Note: $\sqrt[3]{125}=\sqrt[3]{{5^3}} = 5$

To find the correct expression for the above simplified expression.

Option A: $\frac{\sqrt[3]{4 x}}{5}$

5 can be written as $\sqrt[3]{125}$ .

$$\frac{\sqrt[3]{4 x}}{5}=\frac{\sqrt[3]{4 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{4x}{125} }$

It is not the given simplified expression.

Option B: $\frac{\sqrt[3]{20 x}}{5}$

$$\frac{\sqrt[3]{20 x}}{5}=\frac{\sqrt[3]{20 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{20x}{125} }$

Cancel the common factor in both numerator and denominator.

$$=\sqrt[3]{\frac{4x}{25} }$

It is not the given simplified expression.

Option C: $\frac{\sqrt[3]{100 x}}{5}$

$$\frac{\sqrt[3]{100 x}}{5}=\frac{\sqrt[3]{100 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{100x}{125} }$

Cancel the common factor in both numerator and denominator.

$$=\sqrt[3]{\frac{4 x}{5}}$

It is the given simplified expression.

Option D: $\frac{\sqrt[3]{100 x}}{125}$

$$\frac{\sqrt[3]{100 x}}{125}=\frac{\sqrt[3]{100 x}}{5^3}$

It is not the given simplified expression.

Hence Option C is the correct answer.

$$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}$

3 0

3 years ago

A rancher wants to fence in an area of 1500000 square feet in a rectangular field and then divide it in half with a fence down t

VLD [36.1K]

Answer:

6000 ft

Step-by-step explanation:

Let length of rectangular field=x

Breadth of rectangular field=y

Area of rectangular field= $1500000$ square ft

Area of rectangular field= $l\times b$

Area of rectangular field= $x\time y$

$1500000=xy$

$y=\frac{1500000}{x}$

Fencing used ,P(x)= $x+x+y+y+y=2x+3y$

Substitute the value of y

P(x)= $2x+3(\frac{1500000}{x})$

$P(x)=2x+\frac{4500000}{x}$

Differentiate w.r.t x

$P'(x)=2-\frac{4500000}{x^2}$

Using formula: $\frac{dx^n}{dx}=nx^{n-1}$

$P'(x)=0$

$2-\frac{4500000}{x^2}=0$

$\frac{4500000}{x^2}=2$

$x^2=\frac{4500000}{2}=2250000$

$x=\sqrt{2250000}=1500$

It is always positive because length is always positive.

Again differentiate w.r.t x

$P''(x)=\frac{9000000}{x^3}$

Substitute x=1500

$P''(1500)=\frac{9000000}{(1500)^3}>0$

Hence, fencing is minimum at x=1 500

Substitute x=1 500

$y=\frac{1500000}{1500}=1000$

Length of rectangular field=1500 ft

Breadth of rectangular field=1000 ft

Substitute the values

Shortest length of fence used= $2(1500)+3(1000)=6000 ft$

Hence, the shortest length of fence that the rancher can used=6000 ft

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4 years ago

I'm not quite sure what this means can you explain it for me?

Tems11 [23]

Answer:

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6 0

3 years ago

Read 2 more answers