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2 years ago

PLEASE HELP! will award brainliest! find sin A, sin B, cos A, cos B, tan A, and tan B

Mathematics

1 answer:

tangare [24]2 years ago

5 0

Answer:

Step-by-step explanation:

sin A = 5/13

sin B = 12/13

cos A = 12/13

cos B = 5/13

tan A = 12/5

tan B = 5/12

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So in the thing p=m/v to find m would you times v by p?

EastWind [94]

M = mass

p = density

v = volume

Yes, to find m it would be m = pv.

To find v that would be m/p.

8 0

2 years ago

2 sin x cos x – sin x = 0

solniwko [45]

Answer: PiN, Pi/3+2PiN, 5Pi/3+2PiN

Step-by-step explanation: Use formula sheet

7 0

2 years ago

A researcher working in a Human Resources department was interested in gender and sales figures so he conducted a t-test. The me

irina1246 [14]

Answer:

$d = \frac{78.24 -66.25}{\sqrt{\frac{7^2 +7^2}{2}}}= 1.713$

For the interpretation we consider a value for d small is is between 0-0.2, medium if is between 0.2-0.8 and large if is higher than 0.8.

And on this case 1.713>0.8 so we have a large effect size

This value of d=1.713 are telling to us that the two groups differ by 1.713 standard deviation and we will have a significant difference between the two means.

Step-by-step explanation:

Previous concepts

The Effect size is a "quantitative measure of the magnitude of the experimenter effect. "

The Cohen's d effect size is given by the following formula:

$d = \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1 +s^2_2}{2}}}$

Solution to the problem

And for this case we can assume:

$\bar X_1 =78.24$ the mean for females

$\bar X_2 =66.25$ the mean for males

$s_1 = s_2= 7$ represent the deviations for both groups

And if we replace we got:

$d = \frac{78.24 -66.25}{\sqrt{\frac{7^2 +7^2}{2}}}= 1.713$

For the interpretation we consider a value for d small is is between 0-0.2, medium if is between 0.2-0.8 and large if is higher than 0.8.

And on this case 1.713>0.8 so we have a large effect size

This value of d=1.713 are telling to us that the two groups differ by 1.713 standard deviation and we will have a significant difference between the two means.

4 0

2 years ago

Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.

tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: $\frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3}$ square units

(22)

Similar to (21)

Area = $216\sqrt{3}$ square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

$altitude=\frac{\sqrt{3}}{2}*side$

$side = \frac{36}{\sqrt{3}}$

Hence, area of the hexagon will be: $648\sqrt{3}$ square units

(24)

Given is the inradius of an equilateral triangle.

$Inradius = \frac{\sqrt{3}}{6}*side$

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = $\frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3}$ square units

4 0

2 years ago

Which of the following is the equation of a line perpendicular to the line y = -10x + 1, passing through the point (5,7)?

Viktor [21]

Line 1;
y=-10x+1
Gradient m= -10
Gradient of line 2= 1/10
$\frac{y-5}{x-7} = \frac{1}{10}$
y-5= $\frac{1}{10} {x-7}$
y-5= $\frac{1}{10} x- \frac{7}{10}$
y= $\frac{1}{10} x- \frac{43}{10}$

6 0

2 years ago

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