At a certain college the ratio of men to women is 6 to 5. If there are 3520 total students how many men are there.
1 answer:
Answer:
1920 men are there in college.
Step-by-step explanation:
Given the statement: At a certain college, the ratio of men to women is 6 to 5. If there are 3520 total students.
Ratio states that it is just a comparison between, or a relating of, two different things.
i.e a to b or a: b
Ratio of men to women:
Men : Women = 6: 5
Let x be the number.
Total number of Men in college = 6x and Total number of women = 5x
Since, total number of students = 3520
⇒
Combine like terms;
11x = 3520
Divide by 11 on both sides we get;
x = 320
Therefore, total number of men in college = 6x = 6(320) = 1920
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Answer:
50%
Step-by-step explanation:
68-95-99.7 rule
68% of all values lie within the 1 standard deviation from mean
95% of all values lie within the 1 standard deviation from mean
99.7% of all values lie within the 1 standard deviation from mean
The distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4.
68% of all values lie within the 1 standard deviation from mean =
=
95% of all values lie within the 2 standard deviation from mean =
=
99.7% of all values lie within the 3 standard deviation from mean =
=
Refer the attached figure
P(43<x<55)=2.5%+13.5%+34%=50%
Hence The approximate percentage of light bulb replacement requests numbering between 43 and 55 is 50%
<h3>Answer: 28</h3>
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Explanation:
Method 1
Imagine a table with 8 rows and 8 columns to represent all possible match-ups. You can actually draw out this table or just think of it as a thought experiment.
There are 8*8 = 64 entries in the table. Along the northwest diagonal, we have each team pair up with itself. This is of course silly and impossible. We cross off this entire diagonal so we drop to 64-8 = 56 entries.
Then notice that the lower left corner is a mirror copy of the upper right corner. A match-up like AB is the same as BA. So we must divide by 2 to get 56/2 = 28 different matches.
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Method 2
There are 8 selections for the first slot, and 8-1 = 7 selections for the second slot. We have 8*7 = 56 permutations and 56/2 = 28 combinations.
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Method 3
Use the nCr combination formula with n = 8 and r = 2
There are 28 combinations possible. Order doesn't matter (eg: match-up AB is the same as match-up BA).
Notice how the (8*7)/2 expression is part of the steps shown above in the nCr formula.