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Vedmedyk [2.9K]
3 years ago
10

8

Mathematics
2 answers:
Rainbow [258]3 years ago
8 0

Answer:you would use a demand chart

Step-by-step explanation:

Citrus2011 [14]3 years ago
6 0

Answer:

<u>C. A demand schedule.</u>

Step-by-step explanation:

The demand curve is a visual representation of how many units of a good or service will be bought at each possible price. It plots the relationship between quantity and price that's been calculated on the <u>demand schedule</u>, which is a table that shows <u>exactly how many units</u> of a good or service will be <u>purchased at various prices</u>.

As you can see in the chart below, the price is on the <u>vertical (y) axis</u>, and the quantity is on the <u>horizontal (x) axis</u>. This chart plots the <u>conventional relationship</u> between price and quantity. The <u>lower</u> the price, the <u>higher</u> the quantity <u>demanded</u>. As the price <u>decreases</u> from p0 to p1, the quantity <u>increases</u> from q0 to q1.

<u>Key words and Phrases: </u>

quantity, price, demand, good, service, demand curve, demand schedule

Want to learn more about <u>demand schedules</u>?

Click here to learn more: brainly.com/question/12727568

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A manufacturer finds that the revenue generated by selling of cortan commodity is given by function R(x)=80x-0.2x^ 2 , where he
Nina [5.8K]

The maximum units is 200 and , Total revenue is $8,000

<u>Step-by-step explanation:</u>

Here we have , A manufacturer finds that the revenue generated by selling of cortan commodity is given by function R(x)=80x-0.2x^ 2 , where he maximum reveremany should be manufactured to obtain this maximum units .Let's find out:

We have following function as R(x)=80x-0.2x^ 2 . Let's differentiate this and equate it to zero to find value of x for which the function is maximum!

⇒ R(x)=80x-0.2x^ 2

⇒ \frac{d(R(x))}{dx}=\frac{d(80x-0.2x^ 2)}{dx}

⇒ \frac{d(R(x))}{dx}=\frac{d(80x)}{dx}-\frac{d(0.2x^ 2)}{dx}}

⇒ 0=80-2x(0.2)

⇒ \frac{80}{0.4}=x

⇒ x=200

Now , Value of function at x=200 is :

⇒ R(200)=80(200)-0.2(200)^ 2

⇒ R(200)=16000-8000

⇒ R(200)=8000

Therefore , The maximum units is 200 and , Total revenue is $8,000

7 0
3 years ago
What’s the Greatest common factor of 12 and 60?
rewona [7]

12 is your answer

12 x 1 = 12

12 x 5 = 60

hope this helps

3 0
4 years ago
Read 2 more answers
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bezimeni [28]

Answer:

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Step-by-step explanation:

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43,300!!

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irga5000 [103]
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