Answer:
Step-by-step explanation:
4.
a)
P = 2width + 2length
8x = 2x + 2 length; 8x-2x = 2 length; 6x=2 length
length = 3x
b)
sides= 1/4 of 3x = 3x/4
perimeter of square = 4* side = 4*3x/4 = 3x
c)
x= 4
P rectangle =8x= 8*4= 32
P square = 3x = 3*4 = 12
32-12 = 20 cm greater is the P rectangle than P of square
d)
A rectangle = 2x*x = 2*4*4 = 32
A square =(3x/4)² = (3*4/4)² = 9
32-9 = 23 cm² greater is the A rectangle than A of square
5.
4Comic+1 Nonfiction
4comic = 8y so 1 comic = 2y
1 nonfiction = (3+7y)+ 2y
a)
1 nonfiction = 7y+2y+3 = 9y+3
b)
total= 8y+9y+3 = 17y+3
if y=4
total = 17*4 +3 = $71
Answer:
$2.79 per pound of apples.
0.36 pounds per dollar.
The unit rate representing cost of per pound apples is typically used.
Step-by-step explanation:
We have been given that the weekly ad for a local grocery store advertises a 5 pound bag of organic apples for $13.95.
Since we know when rates are expressed as a quantity of 1, such as 100 meter per second or 5 miles per hour, they are called unit rates. We need to have 1 in our denominator to express two quantities as unit rate.
Let us find the unit rate in terms of cost of per pound bag of apples.
Therefore, our unit rate will be $2.79 per pound of apples.
Let us find unit rate of pounds of apples per dollar.
Therefore, our another unit rate will be 0.36 pounds per dollar.
Since, we purchase apples or other items according to their price per piece or their price per pound in our daily life, therefore, the unit rate representing cost of per pound apples is typically used.
Answer:
domain: x>3/5
Step-by-step explanation:
First we need to derive our function g(x) to get a new function g'(x)
To do this we will have to apply chain rule because we have an inner and outer functions.
Our G(x) = square root(3-5x)
Chain rule formula states that: d/dx(g(f(x)) = g'(f(x))f'(x)
where d/dx(g(f(x)) = g'(x)
g(x) is the outer function which is x^1/2
f(x) is our inner function which is 3-5x
therefore f'(x)= 1/2x^(-1/2) and f'(x) = -5
g'(f(x)) = -1/2(3-5x)^(-1/2)
Applying chain rule then g'(x) = 1/2 (3-5x)^(-/1/2)*(-5)
But the domain is the values of x where the function g'(x) is not defined
In this case it will be 3-5x > 0, because 3-5x is a denominator and anything divide by zero is infinity/undefined
which gives us x >3/5
The missing segment is 25
