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EastWind [94]
2 years ago
10

What is the greatest common factor of 48, 24, and 45?

Mathematics
1 answer:
pshichka [43]2 years ago
4 0

Answer:

3

Step-by-step explanation:

Let's write the factors:

48's factors are = 1, 2, 3, 4, 6, 8, 12, 16, 24 and 48.

24's factors are = 1, 2, 3, 4, 6, 8, 12, 24.

45's factors are =1, 3, 5, 9, 15 and 45.

The greatest number that is in all three of these lists of factors is 3!

So, 3 is the greatest common factor between all three numbers!

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Vlad1618 [11]

Answer:

The third option

Step-by-step explanation:

This is because you plug in 1 as a test into each of the equations and see if it equals to 12.25. It works for the third option. To verify that you can also plug in different x values and see if they match the y value.

6 0
3 years ago
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MATH - look at the picture and i will mark you as brainliset if you answer correctly.
mote1985 [20]

Answer:

C is the answer

Step-by-step explanation:

It's very obvi lol

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3 years ago
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Which of the following are true statements? Select all that apply.
Gennadij [26K]

Since sine and cosecant are reciprocals, when one has a maximum the other has a minimum and vice versa.


That's choices B & D


Not sure what the question at the end is asking; at 90 degrees and also at -90 degrees the values of sine and cosecant are equal.



3 0
3 years ago
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The green triangle is a dilation of the red triangle with a scale factor of s=1/3 and the center of dilation is at the point (4,
klasskru [66]

Given:

The scale factor is s=\dfrac{1}{3} and the center of dilation is at the point (4,2).

Red is original figure and green is dilated figure.

To find:

The coordinates of point C' and point A.

Solution:

Rule of dilation: If a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

According to the given information, the scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Let us assume the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Therefore, the coordinates of Point C' are C'(2,5).

We assumed that point A is A(m,n).

Using (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

\dfrac{1}{3}(m-4)=8-4

(m-4)=3(4)

m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

5 0
3 years ago
12 ten thousands, 8 thousands,14 hundreds, 7 ones in standard form
coldgirl [10]
12 x 10000 = 120000
8 x 1000 = 8000
14 x 100 = 1400
7 x 1 = 7

120000 + 8000 + 1400 + 7
129407 is your answer

hope this helps
8 0
3 years ago
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