Distance = rate * time (I will abbreviate as d = rt)
d = rt, so r = d/t
r = 20mi/24min
= 0.833333 mi/min.
d = rt again for the new time
d = 0.8333333 mi/min * 6 min = 5 miles
20% of 75 = 15
75 - 15 = £60
It should be c) £60
Answer:
180 fb*lb
45 ft*lb
Step-by-step explanation:
We have that the work is equal to:
W = F * d
but when the force is constant and in this case, it is changing.
therefore it would be:

Where a = 0 and b = 30.
F (x) = 0.4 * x
Therefore, we replace and we would be left with:

We integrate and we have:
W = 0.4 / 2 * x ^ 2
W = 0.2 * (x ^ 2) from 0 to 30, we replace:
W = 0.2 * (30 ^ 2) - 0.2 * (0 ^ 2)
W = 180 ft * lb
Now in the second part it is the same, but the integral would be from 0 to 15.
we replace:
W = 0.2 * (15 ^ 2) - 0.2 * (0 ^ 2)
W = 45 ft * lb
It shows -3, -2 in the graph in standard form i believe it’s y= -5