Answer:
a) 0.59871
b) 0.22663
e) 0.95994
Step-by-step explanation:
The height of adult males on a given South Pacific Island is approximately normally distributed with mean 65 inches and standard deviation of 4 inches.
We solve using z score
z = (x-μ)/σ, where
x is the raw score
μ is the population mean = 65 inches
σ is the population standard deviation = 4 inches
a). Taller than 64 inches
This means x > 64
Hence,
64 - 65/4
=- 1/4 = -0.25
P-value from Z-Table:
P(x<64) = 0.40129
P(x>64) = 1 - P(x<64) = 0.59871
b.) shorter than 62 inches
Hence,
62 - 65/4
=- 3/4 =- 0.75
P-value from Z-Table:
P(x<62) = 0.22663
c.) between 64 inches and 68 inches
Hence,
for 64 inches
64 - 65/4
=- 1/4 = -0.25
P-value from Z-Table:
P(x = 64) = 0.40129
For 68 inches
Hence,
68 - 65/4
= 3/4= 0.75
P-value from Z-Table:
P(x = 68) = 0.77337
d.) between 58 and 68 inches
e.) taller than 58 inches
Hence,
58 - 65/4
= -6/4 = -1.5
P-value from Z-Table:
P(x<58) = 0.040059
P(x>58) = 1 - P(x<58) = 0.95994
Figure is missing, so i have attached it.
Answer:
it will clear the arch because the height of the archway of the bridge 5 feet from the center is approximately 12.76 ft
Step-by-step explanation:
The standard form of equation of an ellipse is;
x²/a² + y²/b² = 1
From the figure in the image attached, we can see that the radius is; a = 52/2 = 26 ft
While the value of b = 13 ft
Thus;
x²/26² + y²/13² = 1
x²/676 + y²/169 = 1
We want to find the height of the archway of the bridge 5 feet from the center.
Thus, we will plug in 5 for x to get;
5²/676 + y²/169 = 1
(25/676) + (y²/169) = 1
Multiply through by 676 to get;
25 + 4y² = 676
4y² = 676 - 25
y² = 651/4
y² = 162.75
y = 12.76 ft
Thus height of the truck is 12 ft and so it will clear the arch because the height of the archway of the bridge 5 feet from the center is approximately 12.76 ft
13x+25=0
13x+25-25=0-25 Since two opposites added give zero, remove them from the expression 13x=-25