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Anna007 [38]
2 years ago
6

Plssss help meeee!!!!!!!​

Mathematics
1 answer:
svp [43]2 years ago
7 0

Answer:

Both ran the same area

Step-by-step explanation:

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There are 50 students in a class. If 14% are absent on a particular day, find the number of students present in the class. What
Tcecarenko [31]

Answer:

i THINK 43% but im not for sure

Step-by-step explanation:

14% of 50 is 7

so 50-7=43

43(percent there)+7(percent gone)=50 (number of students)

SO 43% is still there.  

SORRY IF IM WRONG have a good night :)

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3 years ago
Help please ASAP i WILL mark brainliest !!!
lisabon 2012 [21]
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Which order pairs lie on the graph f(×)= 128(0.5)×
RoseWind [281]

Answer:

the answer is (1,64)

Step-by-step explanation:

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6 0
2 years ago
PLEASE HURRY :,) WILL GIVE BRAINLEST
GrogVix [38]
B. (-40, -30) because point r is at that point which is a distance of 20 units from point Q.
7 0
3 years ago
Read 2 more answers
Joe earns $14 an hour and Blaine earns $18 per hour. Joe receives a raise of $1.75 every six months, and Blaine receives a raise
Vanyuwa [196]

Answer:

4 interval of six months.

Step-by-step explanation:

Given: Joe earn $14 per hour

           Blaine earn $18 per hour.

           Joe receives a raise of $1.75 every six months

           Blaine receives a raise of $0.75 every six months.

Lets assume the number of six month intervals be "x".

Now, finding the number of six months interval require to get Joe´s earning equal to Blaine earning.

Forming an equation to find the six month interval

⇒ 14+(1.75\times x)= 18+(0.75\times x)

Solving the equation to find the value of x

⇒ 14+1.75x= 18+0.75x

subtracting both side by 0.75x

⇒ 14+x= 18

subtracting both side by 14

∴ x= 4

Subtituting the value of x, we will get both Joe and Blaine earning as equal.

14+(1.75\times x)= 18+(0.75\times x)

⇒ 14+(1.75\times 4)= 18+(0.75\times 4)

⇒ \$ 21= \$ 21

Hence, after 4 interval of six months, Joe to earn same hourly rate as Blaine.

4 0
3 years ago
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