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Readme [11.4K]
2 years ago
15

2900 people attended a football game. 1595 of the people attending supported the home team, while 1305 supported the visiting te

am. What percentage of people attending supported the home team?'
PLEASE ANSWER
Mathematics
1 answer:
amid [387]2 years ago
6 0
100%-> 2900
1%-> 2900/100
=29
29-> 1%
1595->?

1595/29=55

29->1%
1595->1 x 55
=55%

So, 55% is your answer !!
Hope this helps :)
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Which property would be used to show that the product of two rational is always rational
KatRina [158]

You multiply two rational numbers by multiplying numerators and denominators with each other. So, you have

\dfrac{a}{b} \times \dfrac{c}{d} = \dfrac{ac}{bd}

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3 0
3 years ago
The equation of a circle is (x + 6)^2 + (y - 4)^2 = 16. The point (-6, 8) is on the circle.
pantera1 [17]

Answer:

y = 8 is the equation of tangent.

Step-by-step explanation:

The equation of the tangent to the circle at (-6,8) is of the form:

y = mx + c

where m is the slope of the tangent and c is the y-intercept.

The point (-6,8) lies on the circle and the tangent line as well.

Hence (-6,8) satisfies the line equation:

8 = m(-6) + c ⇒ c-6m = 8 -------------1

We know that slope of two perpendicular lines are related as:

m_{1}\times m_{2}=-1

At any point on the circle, the normal line at a point is always perpendicular to the tangent line at that point.

Hence :

m_{normal} \times m_{tangent}=-1

We can find the slope of the normal at point (-6,8) as it passes through the centre of the circle (-6,4) by using the two-points formula for slope.

m=\frac{y_2-y_1}{x_2-x_1}

         =\frac{8-4}{-6+6}

          = ∞

Slope of the normal is infinity and hence slope of tangent is -1/∞ = 0

Hence m=0

Putting m=0 in equation 1 we get:

c = 8

The equation of tangent line at (-6,8) is:

y = 8

6 0
3 years ago
NEED HELP PLS
AnnZ [28]

Answer:

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6 0
3 years ago
Find the value of the six trig functions given the triangle below.
Y_Kistochka [10]

\text{Here,}\\\\\text{Opposite side,}~ O = 2\\\\\text{Hypotenuse,}~ H   = \sqrt 5 \\\\\text{Adjacent side,}~ A = \sqrt{5-4} = \sqrt 1  =1  ~~ ;[\text{By using Pythagorean theorem}]\\\\\\\sin \theta = \dfrac{O}H = \dfrac 2{\sqrt 5}\\\\\\\cos \theta = \dfrac{A}{H} = \dfrac{1}{\sqrt 5} \\ \\\\ \tan \theta = \dfrac{O}{A} = \dfrac 21 = 2

csc \theta = \dfrac{1}{\sin \theta} = \dfrac{\sqrt 5}2\\\\\\\sec \theta = \dfrac{1}{\cos \theta} = \sqrt 5  \\\\\\\cot \theta = \dfrac 1{\tan \theta} = \dfrac 12

5 0
2 years ago
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prohojiy [21]

Answer:

x=-4

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4 0
3 years ago
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