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3 years ago

A cook has 5 and 5/8 cups of flour he uses 2/3 on Saturday morning how much flour does he use in saturday morning

Mathematics

1 answer:

solong [7]3 years ago

7 0

Answer:

2/3

this question doesn't make sense

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X/2 = 8<br> anyone know how to work this out?

Alexus [3.1K]

X/2 = 8

▶ ️2 = 8 × X. (transposing X to RHS )

▶️ 2 = 8X

▶ ️X = 8/2. (transposing 2 to RHS )

▶️ X = 4

hence the value of X is 4.

3 0

3 years ago

Read 2 more answers

Given: || EIJ GJI Prove: JIK IJL

EastWind [94]

Jk+jik+ijl goodluck :)

6 0

3 years ago

Consider the quadratic function f(x)=−x^2+x+30

yaroslaw [1]

Answer:

The smallest xx-intercept is $x = -5$

The largest xx-intercept is $x = 6$

The yy-intercept is $y = 30$ .

Step-by-step explanation:

Given a quadratic function in the following format:

$f(x) = ax^{2} + bx + c = 0, a \neq 0$

The x-values of the x-intercepts are $x_{1}, x_{2}$ , given by the following formulas.

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

We have that:

$f(x) = -x^{2} + x + 30$

This is not in the format above. I will multiply by (-1), so we have:

$f(x) = x^{2} - x - 30$

So, $a = 1, b = -1, c = -30$

$\bigtriangleup = b^{2} - 4ac = (-1)^{2} - 4*(1)*(-30) = 1 + 120 = 121$

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a} = \frac{-(-1) + \sqrt{121}}{2(1)} = \frac{12}{2} = 6$

$x_{2} = \frac{-b + \sqrt{\bigtriangleup}}{2*a} = \frac{-(-1) - \sqrt{121}}{2(1)} = \frac{-10}{2} = -5$

This means that

The smallest xx-intercept is $x = -5$

The largest xx-intercept is $x = 6$

The y-intercept is the value of f(x) when x = 0. So

$f(x)=−x^{2}+x+30$

$f(0) = 30$

The yy-intercept is $y = 30$ .

5 0

3 years ago

Given cos(x)=1/2, what is the value of cos(x+pi)?

patriot [66]

Answer:

-1/2

Step-by-step explanation:

cos(x+pi) = -cos(x), so the answer is -1/2.

8 0

2 years ago

6.) Alan, Becky, Jesus, and Mariah are four students in the chess club. If two of these students will be selected to represent t

Artist 52 [7]

Let's begin by listing out the information given to us:

There are four students: n = 4

Number of students to be selected: r = 2

To calculate the combination of 2 students to be chosen, we use:

$\begin{gathered} ^4C_2=\frac{n!}{(n-r)!}=\frac{4!}{(4-2)!}=\frac{4!}{2!} \\ ^4C_2=\frac{4\cdot3\cdot2\cdot1}{2\cdot1}=\frac{4\cdot3}{1}=12 \\ ^4C_2=12 \end{gathered}$

Therefore, there 12 possible combinations from these

3 0

2 years ago