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2 years ago

A cook has 5 and 5/8 cups of flour he uses 2/3 on Saturday morning how much flour does he use in saturday morning

Mathematics

1 answer:

solong [7]2 years ago

7 0

Answer:

2/3

this question doesn't make sense

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HELP ME PLEASE!!!!!!

gladu [14]

Answer:

6x²y²

Step-by-step explanation:

6: 1 2 3 6

18: 1 2 3 6 9 18

36: 1 2 3 4 6 9 12 18 36

the common factor for 6 18 and 36 are

1 2 3 6

x² = x × x

y³ = y × y × y

x³ = x × x × x

y³ = y × y × y

x³ = x × x × x

y² = y × y

the common factor are for x and y are

x² y²

Multiply the GCF of the numerical part 6 and the GCF of the variable part x² y² to get 6x² y²

5 0

2 years ago

Find the center and radius for the circle by the equations: x2 + y2 + 5x - y + 2 = 0.

lord [1]

X2+5x+y2-y=-2
X2+2*5x2+(5/2)^2-(5/2)^2+y2-2*y/2+(1/2)^2-(1/2)^2=-2
(x+5/2)^2+(y-1/2)^2-13/2=-2
(x+5/2)^2+(y-1/2)^2=9/2
So centre =(-5/2,1/2)
Radius=(9/2)^(1/2)

7 0

3 years ago

What is the factorization of the expression below <br> x2-12x+36

Lera25 [3.4K]

Answer:

(x-6)^2

Step-by-step explanation:

3 0

2 years ago

)The ratio of X's to O's is 15 over 10. . Use the image below to determine another ratio for X's to O's: Image with 15 Xs and 10

luda_lava [24]

Answer:

2:3

Step-by-step explanation:

The common factor between 10 and 15 is 5.

5 goes into 10 twice and 15 three times.

$\frac{15}{10}$ ÷ $\frac{5}{5} = \frac{2}{3}$

4 0

2 years ago

Can anyone help me out on this question?

svp [43]

Firstly , we will check continuity at x=1

we can use method

Suppose, f(x) is continuous at x=c

then it must satisfy

$\lim_{x \to c} f(x)=f(c)$

$\lim_{x \to 1} f(x)=f(1)$

firstly , we can find limit

$\lim_{x \to 1-} f(x)= \lim_{x \to 1-}(x+3)=1+3=4$

$\lim_{x \to 1+} f(x)= \lim_{x \to 1-}(3x+1)=3*1+1=4$

so, we get

$\lim_{x \to 1} f(x)= 4$

now, we can find f(1)

$f(1)=3*1+1=4$

so, we got

$\lim_{x \to 1} f(x)=f(1) =4$

so, this is continuous at x=1

Hence , option-D...........................Answer

5 0

3 years ago