Do you mean 3/√11 ? In this case, you'll have to multiply both, numerator and denominator by the denominator ...
Well let's see:
The first letter can be any one of 26 .
For each one . . .
The second letter can be any one of the remaining 25.
For each one . . .
The third letter can be any one of the remaining 24.
For each one . . .
The two digits can be any number from 01 to 98 ...
except 11, 22, 33, 44, 55, 66, 77, or 88. (No repetition.)
There are 90 of them.
So the total number of possibilities is (26 · 25 · 24 · 90) .
When I multiply that out, I get 1,404,000 .
I don't know how you got your number, so I can't comment on your
method, but I did find something interesting about your number:
If I assume that you did the three letters the same way I did, then
if I divide your number by (26·25·24), the quotient will show me
how you handled the two digits.
1,263,600 / (26·25·24) = 81 .
That's very intriguing, because it's so close to the 90 sets of digits
that I used. But I don't know what it means, or if it means anything
at all.
Statistical because you would need to know what cheetahs weigh. same goes for leopards though.
Answer:
The confidence interval would be given by this formula
For the 95% confidence interval the value of 
and 
, with that value we can find the quantile required for the interval in the normal standard distribution.
The margin of error for this case is given by:
And replacing we got:
And replacing into the confidence interval formula we got:
And the 95% confidence interval would be given (0.4941;0.5459).
Step-by-step explanation:
Data given and notation
n=1000 represent the random sample taken
estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage
represent the significance level (no given, but is assumed)
Solution to the problem
The confidence interval would be given by this formula
For the 95% confidence interval the value of and , with that value we can find the quantile required for the interval in the normal standard distribution.
The margin of error for this case is given by:
And replacing we got:
And replacing into the confidence interval formula we got:
And the 95% confidence interval would be given (0.4941;0.5459).
